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ChemistryJEE Main 2 Apr 2026, Shift 2·Q5·MCQ·Easy–moderate

Solutions · Osmotic pressure of mixed solutions

Solution A is prepared by dissolving 1 g of a protein (molar mass = 50000 g mol−1^{-1}) in 0.5 L of water at 300 K. Its osmotic pressure is x bar. Solution B is made by dissolving 2 g of same protein in 1 L of water at 300 K. Osmotic pressure of solution B is y bar. Entire solution of A is mixed with entire solution of B at same temperature. The osmotic pressure of resultant solution is z bar. x, y and z respectively are :

(R=0.083R = 0.083 L bar mol−1^{-1} K−1^{-1})

  1. (1)9.96×10−49.96\times10^{-4}; 9.96×10−49.96\times10^{-4}; 9.96×10−49.96\times10^{-4}
  2. (2)9.96×10−49.96\times10^{-4}; 9.96×10−49.96\times10^{-4}; 19.92×10−419.92\times10^{-4}
  3. (3)4.98×10−44.98\times10^{-4}; 4.98×10−44.98\times10^{-4}; 9.96×10−49.96\times10^{-4}
  4. (4)4.98×10−44.98\times10^{-4}; 4.98×10−44.98\times10^{-4}; 4.98×10−44.98\times10^{-4}

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See the full 2 Apr 2026, Shift 2 paper