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MathsJEE Main 2 Apr 2026, Shift 2·Q20·MCQ·Moderate

Differential Equations · Bernoulli differential equation

Let x=x(y)x = x(y) be the solution of the differential equation 2y2dxdy−2xy+x2=02y^2\dfrac{dx}{dy} - 2xy + x^2 = 0, y>1y > 1, x(e)=ex(e) = e. Then x(e2)x(e^2) is equal to:
  1. (1)32e2\dfrac32e^2
  2. (2)23e2\dfrac23e^2
  3. (3)e2e^2
  4. (4)2e22e^2

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