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ChemistryJEE Main 21 Jan 2026, Shift 2·Q23·Numerical·Moderate

Solutions · Relative lowering of vapour pressure

A substance ‘X' (1.5 g) dissolved in 150 g of a solvent ‘Y' (molar mass =300= 300 g mol−1^{-1}) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent ‘Y' is ×10−2\times10^{-2}. (Nearest integer)

[Given : KbK_\mathrm{b} of the solvent =5.0= 5.0 K kg mol−1^{-1}]

Assume the solution to be dilute and no association or dissociation of X takes place in solution.

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