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MathsJEE Main 21 Jan 2026, Shift 2·Q24·Numerical·Moderate

Binomial Theorem · Products of binomial coefficients

If (115C0+115C1)(115C1+115C2)⋯(115C12+115C13)=α1314C0 14C1⋯14C12,\left(\frac{1}{{}^{15}C_0} + \frac{1}{{}^{15}C_1}\right)\left(\frac{1}{{}^{15}C_1} + \frac{1}{{}^{15}C_2}\right)\cdots\left(\frac{1}{{}^{15}C_{12}} + \frac{1}{{}^{15}C_{13}}\right) = \frac{\alpha^{13}}{{}^{14}C_0\,{}^{14}C_1\cdots{}^{14}C_{12}}, then 30α30\alpha is equal to .

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