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MathsJEE Main 21 Jan 2026, Shift 2·Q5·MCQ·Moderate

Conic Sections · Locus of centroid on parabola

Let y2=12xy^2 = 12x be the parabola with its vertex at OO. Let PP be a point on the parabola and AA be a point on the xx-axis such that ∠OPA=90∘\angle OPA = 90^\circ. Then the locus of the centroid of such triangles OPAOPA is:
  1. (1)y2−6x+4=0y^2 - 6x + 4 = 0
  2. (2)y2−9x+6=0y^2 - 9x + 6 = 0
  3. (3)y2−2x+8=0y^2 - 2x + 8 = 0
  4. (4)y2−4x+8=0y^2 - 4x + 8 = 0

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