AktiraAktira JEE
PhysicsJEE Main 22 Jan 2026, Shift 1·Q11·MCQ·Easy–moderate

Nuclei · Nuclear structure

The minimum frequency of photon required to break a particle of mass 15.348 amu into 4α4\alpha particles is kHz. [mass of He nucleus =4.002= 4.002 amu, 1 amu =1.66×10−27= 1.66\times10^{-27} kg, h=6.6×10−34h = 6.6\times10^{-34} J.s and c=3×108c = 3\times10^{8} m/s]
  1. (1)9×10199\times10^{19}
  2. (2)9×10209\times10^{20}
  3. (3)14.94×102014.94\times10^{20}
  4. (4)14.94×101914.94\times10^{19}

Video solution coming soon

We're animating every PYQ step by step. Subscribe to get them first.

Subscribe

See the full 22 Jan 2026, Shift 1 paper

More on Nuclear structure