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MathsJEE Main 22 Jan 2026, Shift 2·Q20·MCQ·Tough

Binomial Theorem · Sums of binomial coefficients

Let CrC_r denote the coefficient of xrx^r in the binomial expansion of (1+x)n(1 + x)^n, n∈Nn \in \mathbb{N}, 0≤r≤n0 \le r \le n. If Pn=C0−C1+223C2−234C3+⋯+(−2)nn+1Cn,P_n = C_0 - C_1 + \frac{2^2}{3}C_2 - \frac{2^3}{4}C_3 + \cdots + \frac{(-2)^n}{n+1}C_n, then the value of ∑n=1251P2n\displaystyle\sum_{n=1}^{25}\frac{1}{P_{2n}} equals.
  1. (1)580
  2. (2)525
  3. (3)650
  4. (4)675

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