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MathsJEE Main 22 Jan 2026, Shift 2·Q4·MCQ·Moderate

Complex Numbers · Solving equations in conjugate

Let S={z∈C:4z2+zˉ=0}S = \left\{z \in \mathbb{C} : 4z^2 + \bar{z} = 0\right\}. Then ∑z∈S∣z∣2\displaystyle\sum_{z\in S}\lvert z\rvert^2 is equal to:
  1. (1)316\dfrac{3}{16}
  2. (2)764\dfrac{7}{64}
  3. (3)116\dfrac{1}{16}
  4. (4)564\dfrac{5}{64}

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