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ChemistryJEE Main 24 Jan 2026, Shift 2·Q18·MCQ·Easy–moderate

Solutions · Henry law gas solubility

At 298 K, the mole percentage of NX2(g)\ce{N2(g)} in air is 80%. Water is in equilibrium with air at a pressure of 10 atm. What is the mole fraction of NX2(g)\ce{N2(g)} in water at 298 K ? (KHK_\mathrm{H} for NX2\ce{N2} is 6.5×1076.5\times10^{7} mm Hg)
  1. (1)1.23×10−71.23\times10^{-7}
  2. (2)1.17×10−41.17\times10^{-4}
  3. (3)9.35×1059.35\times10^{5}
  4. (4)9.35×10−59.35\times10^{-5}

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