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MathsJEE Main 24 Jan 2026, Shift 2·Q22·Numerical·Easy–moderate

Conic Sections · Locus and eccentricity of ellipse

Let (h,k)(h, k) lie on the circle C:x2+y2=4C : x^2 + y^2 = 4 and the point (2h+1,3k+2)(2h + 1, 3k + 2) lie on an ellipse with eccentricity ee. Then the value of 5e2\dfrac{5}{e^2} is equal to .

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