AktiraAktira JEE
PhysicsJEE Main 24 Jan 2026, Shift 2·Q18·MCQ·Easy–moderate

Thermodynamics · Thermodynamic processes

10 mole of an ideal gas is undergoing the process shown in the figure. The heat involved in the process from P1P_1 to P2P_2 is α\alpha Joule (P1=21.7P_1 = 21.7 Pa and P2=30P_2 = 30 Pa, Cv=21C_v = 21 J/K.mol, R=8.3R = 8.3 J/mol.K). The value of α\alpha is .
  1. (1)24
  2. (2)15
  3. (3)21
  4. (4)28

Video solution coming soon

We're animating every PYQ step by step. Subscribe to get them first.

Subscribe

See the full 24 Jan 2026, Shift 2 paper

More on Thermodynamic processes