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ChemistryJEE Main 28 Jan 2026, Shift 2·Q5·MCQ·Easy–moderate

Thermodynamics · Log k versus 1/t plot

The plot of log⁡10K\log_{10}K vs 1T\dfrac{1}{T} gives a straight line. The intercept and slope respectively are (where K is equilibrium constant).
  1. (1)2.303RΔH∘\dfrac{2.303R}{\Delta H^\circ}, 2.303RΔS∘\dfrac{2.303R}{\Delta S^\circ}
  2. (2)ΔS∘2.303R\dfrac{\Delta S^\circ}{2.303R}, −ΔH∘2.303R-\dfrac{\Delta H^\circ}{2.303R}
  3. (3)−ΔS∘R2.303-\dfrac{\Delta S^\circ R}{2.303}, ΔH∘R2.303\dfrac{\Delta H^\circ R}{2.303}
  4. (4)−ΔH∘2.303R-\dfrac{\Delta H^\circ}{2.303R}, ΔS∘2.303R\dfrac{\Delta S^\circ}{2.303R}

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