AktiraAktira JEE
MathsJEE Main 28 Jan 2026, Shift 2·Q10·MCQ·Moderate

Conic Sections · Confocal ellipse and hyperbola

Let the ellipse E:x2144+y2169=1E : \dfrac{x^2}{144} + \dfrac{y^2}{169} = 1 and the hyperbola H:x216−y2λ2=−1H : \dfrac{x^2}{16} - \dfrac{y^2}{\lambda^2} = -1 have the same foci. If ee and LL respectively denote the eccentricity and the length of the latus rectum of HH, then the value of 24(e+L)24(e + L) is :
  1. (1)296
  2. (2)126
  3. (3)148
  4. (4)67

Video solution coming soon

We're animating every PYQ step by step. Subscribe to get them first.

Subscribe

See the full 28 Jan 2026, Shift 2 paper