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MathsJEE Main 28 Jan 2026, Shift 2·Q12·MCQ·Tough

Circles · Locus of intersection of chords

Let the circle x2+y2=4x^2 + y^2 = 4 intersect xx-axis at the points A(a,0)A(a, 0), a>0a > 0 and B(b,0)B(b, 0). Let P(2cos⁡α,2sin⁡α)P(2\cos\alpha, 2\sin\alpha), 0<α<π20 < \alpha < \dfrac{\pi}{2} and Q(2cos⁡β,2sin⁡β)Q(2\cos\beta, 2\sin\beta) be two points such that (α−β)=π2(\alpha - \beta) = \dfrac{\pi}{2}. Then the point of intersection of AQAQ and BPBP lies on :
  1. (1)x2+y2−4y−4=0x^2 + y^2 - 4y - 4 = 0
  2. (2)x2+y2−4x−4=0x^2 + y^2 - 4x - 4 = 0
  3. (3)x2+y2−4x−4y=0x^2 + y^2 - 4x - 4y = 0
  4. (4)x2+y2−4x−4y−4=0x^2 + y^2 - 4x - 4y - 4 = 0

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