3D Geometry · Image of point in a line

Let

Q(a, b, c)

be the image of the point

P(3, 2, 1)

in the line

\dfrac{x-1}{1} = \dfrac{y}{2} = \dfrac{z-1}{1}

. Then the distance of

Q

from the line

\dfrac{x-9}{3} = \dfrac{y-9}{2} = \dfrac{z-5}{-2}

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