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MathsJEE Main 5 Apr 2026, Shift 1·Q10·MCQ·Easy–moderate

Circles · Maximum distance from a circle

Let PP be a moving point on the circle x2+y2−6x−8y+21=0x^2 + y^2 - 6x - 8y + 21 = 0 Then, the maximum distance of PP from the vertex of the parabola x2+6x+y+13=0x^2 + 6x + y + 13 = 0 is equal to:
  1. (1)8
  2. (2)10
  3. (3)12
  4. (4)9

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