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MathsJEE Main 5 Apr 2026, Shift 1·Q25·Numerical·Moderate

Differential Equations · Homogeneous differential equations

Let y=y(x)y = y(x) be the solution of the differential equation xsin⁡(yx)dy=(ysin⁡(yx)−x)dx,y(1)=π2x\sin\left(\frac{y}{x}\right)dy = \left(y\sin\left(\frac{y}{x}\right) - x\right)dx,\quad y(1) = \frac{\pi}{2} and let α=cos⁡(y(e12)e12)\alpha = \cos\left(\dfrac{y\left(e^{12}\right)}{e^{12}}\right). Then the number of integral value of pp, for which the equation x2+y2−2px+2py+α+2=0x^2 + y^2 - 2px + 2py + \alpha + 2 = 0 represents a circle of radius r≤6r \le 6, is .

Flawed question. Ill-posed: the solution is cos⁡(y/x)=log⁡ex\cos(y/x) = \log_e x, which exists only for e−1≤x≤ee^{-1} \le x \le e, so y(e12)y(e^{12}) does not exist and α=cos⁡(⋅)=12\alpha = \cos(\cdot) = 12 is impossible; even with the formal α=12\alpha = 12 (r2=2p2−14r^2 = 2p^2 - 14) only p=±3,±4,±5p = \pm3, \pm4, \pm5 give a circle (6 values), while the key 11 also counts pp with r2<0r^2 < 0; no minimal, evident change repairs both. It is shown for completeness and is left out of practice tests.

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