PhysicsJEE Main 5 Apr 2026, Shift 1·Q5·MCQ·Tough

Newton's Laws of Motion · Newton's laws

A wedge Y with mass of 10 kg has all frictionless surfaces and the inclined surface making

37^\circ

with horizontal. A block X with mass 2 kg is placed at the highest point of the wedge as shown in figure is at rest. At

t = 0

wedge (Y) is pulled toward right with constant force (

f

) of 24 N. Taking the block X at rest at

t = 0

, the time taken by it to slide down 8.8 m on the slope, while Y is on the move, is approximately s. (take

\tan(37^\circ) = 3/4

and

g = 10\ \mathrm{m/s^2}

)

(1)2
(2)4
(3) $\sqrt2$
(4) $2\sqrt2$

We corrected a printing error in the original paper

Source printed “A wedge Y with mass of 10 kg and all frictionless surfaces” and “while Y is on the move, is s”; corrected to the intended “… has all frictionless surfaces” and “… is approximately s” (with the printed data the wedge accelerates at 1.34 m/s $^2$ , the block slides at 4.93 m/s $^2$ relative to it and $t = 1.89$ s; the key 2 s takes the wedge acceleration as $24/12 = 2$ m/s $^2$ ).

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Newton's Laws of Motion · Newton's laws

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