ChemistryJEE Main 6 Apr 2026, Shift 2·Q22·Numerical·Easy–moderate

Hydrocarbons · Alkane combustion and free radical chlorination

An alkane (Y) requires 8 moles of oxygen for complete combustion and on chlorination with

\ce{Cl2}

\nu

, (Y) gives only one monochlorinated product (Z). The total number of primary carbon atoms in (Y) is .

We corrected a printing error in the original paper

Source printed “ $\ce{Cl2}$ /hv” (Latin v for $\nu$ ).

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