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ChemistryJEE Main 6 Apr 2026, Shift 2·Q25·Numerical·Easy

Chemical Kinetics · Arrhenius equation activation energy

Decomposition of a hydrocarbon follows the equation k=(5.5×1011 s−1) e−28000 KTk = (5.5\times10^{11}\ \mathrm{s^{-1}})\ e^{\frac{-28000\,\mathrm{K}}{T}}. The activation energy of reaction is kJ mol−1^{-1}. (Nearest Integer)

Given : R=8.3R = 8.3 J K−1^{-1} mol−1^{-1}

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