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MathsJEE Main 6 Apr 2026, Shift 2·Q16·MCQ·Tough

Limits, Continuity & Differentiability · Evaluation of limits

Let lim⁡x→2(tan⁡(x−2))(rx2+(p−2)x−2p)(x−2)2=5\lim_{x\to2}\dfrac{\left(\tan(x-2)\right)\left(rx^2 + (p-2)x - 2p\right)}{(x-2)^2} = 5 for some r,p∈Rr, p \in \mathbb{R}. If the set of all possible values of qq, such that the roots of the equation rx2−px+q=0rx^2 - px + q = 0 lie in (0,2)(0, 2), be the interval (α,β](\alpha, \beta], then 4(α+β)4(\alpha + \beta) equals.
  1. (1)11
  2. (2)13
  3. (3)17
  4. (4)21

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