AktiraAktira JEE
Subscribe
ChemistryJEE Main 2 Apr 2026, Shift 1·Q7·MCQ·Easy–moderate

Electrochemistry · Galvanic cell EMF and reaction

An electrochemical cell is constructed using half cells in the direction of spontaneous change

Fe(OH)X2(s)+2 eX−→Fe(s)+2 OHX−(aq)\ce{Fe(OH)2(s) + 2e- -> Fe(s) + 2OH-(aq)}   E0=−0.88E^0 = -0.88 V

and AgBr(s)+eX−→Ag(s)+BrX−(aq)\ce{AgBr(s) + e- -> Ag(s) + Br-(aq)}   E0=+0.07E^0 = +0.07 V

Which of the following option is correct ?

  1. (1)Overall reaction Fe(s)+2 OHX−1(aq)+2 AgBr(s)⇌Fe(OH)X2(s)+2 Ag(s)+2 BrX−(aq)\ce{Fe(s) + 2OH^{-1}(aq) + 2AgBr(s) <=> Fe(OH)2(s) + 2Ag(s) + 2Br-(aq)}
  2. (2)Ecell0=−0.95E^0_\mathrm{cell} = -0.95 V
  3. (3)Fe is reduced in the electrochemical cell
  4. (4)Ecell0E^0_\mathrm{cell} is an extensive property

Video solution coming soon

We're animating every PYQ step by step. Subscribe to get them first.

Subscribe

See the full 2 Apr 2026, Shift 1 paper