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JEE Main 2026

JEE Main 2 Apr 2026, Shift 1

75 questions. Answers are hidden — tap “Show answer” under each one.

Physics

  1. The dimensional formula of 12ϵ0E2\dfrac12\epsilon_0E^2 (ϵ0=\epsilon_0 = permittivity of vacuum and E=E = electric field) is MaLbTc\mathrm{M^aL^bT^c}. The value of 2a−b+c=2a - b + c = .
    1. (1)0
    2. (2)1
    3. (3)−1-1
    4. (4)2
  2. The diameter of a wire measured by a screw gauge of least count 0.001 cm is 0.08 cm. The length measured by a scale of least count 0.1 cm is 150 cm. When a weight of 100 N is applied to the wire, the extension in length is 0.5 cm, measured by a micrometer of least count 0.001 cm. The error in the measured Young's modulus is α×109 N/m2\alpha\times10^{9}\ \mathrm{N/m^2}. The value of α\alpha is .
    (Ignore the contribution of the load to Young's modulus error calculation)
    1. (1)1.3
    2. (2)1.65
    3. (3)0.13
    4. (4)0.25
  3. The velocity of a particle is given as v⃗=−xi^+2yj^−zk^\vec v = -x\hat i + 2y\hat j - z\hat k m/s. The magnitude of acceleration at point (1, 2, 4) is m/s2\mathrm{m/s^2}.
    1. (1)6\sqrt6
    2. (2)9
    3. (3)33\sqrt{33}
    4. (4)0
  4. The position of an object having mass 0.1 kg as a function of time tt is given as r⃗=(10t2i^+5t3j^)\vec r = \left(10t^2\hat i + 5t^3\hat j\right) m. At t=1t = 1 s, which of the following statements are correct?
    A.The linear momentum p⃗=(2i^+1.5j^)\vec p = \left(2\hat i + 1.5\hat j\right) kg.m/s.
    B.The force acting on the object F⃗=(2i^+3j^)\vec F = \left(2\hat i + 3\hat j\right) N.
    C.The angular momentum of the object about its origin L⃗=15k^\vec L = 15\hat k J s.
    D.The torque acting on the object about its origin τ⃗=20k^\vec\tau = 20\hat k N m.
    Choose the correct answer from the options given below.
    1. (1)A, B and C only
    2. (2)B, C and D only
    3. (3)A, C and D only
    4. (4)A, B and D only
    We corrected a printing error in the original paper

    Source printed “from the option given below”.

  5. Q5 · MCQ · GravitationOpen
    A planet (P1P_1) is moving around the star of mass 2M2M in the orbit of radius RR. Another planet (P2P_2) is moving around another star of mass 4M4M in an orbit of radius 2R2R. Ratio of time periods of revolution of P2P_2 and P1P_1 is .
    1. (1)12\dfrac12
    2. (2)2
    3. (3)4
    4. (4)14\dfrac14
    We corrected a printing error in the original paper

    Source printed “in a orbit”.

  6. A particle is rotating in a circular path and at any instant its motion can be described as θ=5t440−t33\theta = \dfrac{5t^4}{40} - \dfrac{t^3}{3}. The angular acceleration of the particle after 10 seconds is rad/s2\mathrm{rad/s^2}.
    1. (1)150
    2. (2)120
    3. (3)130
    4. (4)170
  7. A parallel plate air capacitor has a capacitance CC. When it is half filled as shown in figure with a dielectric constant K=5K = 5, the percentage increase in the capacitance is .
    1. (1)33.34
    2. (2)66.67
    3. (3)200
    4. (4)400
    We corrected a printing error in the original paper

    Source printed “half filled as show in figure”.

  8. Q8 · MCQ · ThermodynamicsOpen
    Heat is supplied to a diatomic gas at constant pressure. Then the ratio of ΔQ:ΔU:ΔW\Delta Q : \Delta U : \Delta W is .
    1. (1)2 : 3 : 5
    2. (2)5 : 3 : 2
    3. (3)2 : 5 : 7
    4. (4)7 : 5 : 2
  9. Two charged conducting spheres S1S_1 and S2S_2 of radii 8 cm and 18 cm are connected to each other by a wire. After equilibrium is established, the electric fields on S1S_1 and S2S_2 spheres are ES1E_{S1} and ES2E_{S2} respectively. The value of ES1ES2\dfrac{E_{S1}}{E_{S2}} is .
    1. (1)32\dfrac32
    2. (2)23\dfrac23
    3. (3)49\dfrac49
    4. (4)94\dfrac94
    We corrected a printing error in the original paper

    Source printed “the ratio of electric fields on S1S_1 and S2S_2 spheres are ES1E_{S1} and ES2E_{S2}” (extra words “ratio of”).

  10. Q10 · MCQ · WavesOpen
    The equation of a plane progressive wave is given by y=5cos⁡π(200t−x150)y = 5\cos\pi\left(200t - \dfrac{x}{150}\right) where xx and yy are in cm and tt is in second. The velocity of the wave is m/s
    1. (1)120
    2. (2)150
    3. (3)200
    4. (4)300
  11. Two short electric dipoles A and B having dipole moment p1p_1 and p2p_2 respectively are placed with their axis mutually perpendicular as shown in the figure. The resultant electric field at a point x is making an angle of 60∘60^\circ with the line joining points O and x. The ratio of the dipole moments p2/p1p_2/p_1 is .
    1. (1)32\dfrac{\sqrt3}{2}
    2. (2)232\sqrt3
    3. (3)13\dfrac{1}{\sqrt3}
    4. (4)3\sqrt3
  12. For the given circuit (shown in part (A)) the time dependent input voltage vin(t)v_{\mathrm{in}}(t) and corresponding output vo(t)v_o(t) are shown in part (B) and part (C), respectively. Identify the components that are used in the circuit between points X and Y.
    1. (1)
    2. (2)
    3. (3)
    4. (4)
  13. When a coil is placed in a time dependent magnetic field the power dissipated in it is PP. The number of turns, area of the coil and radius of the coil wire are NN, AA and rr respectively. For a second coil's number of turns, area of the coil and radius of the coil wire are 2N2N, 2A2A and 3r3r respectively. When the first coil is replaced with second coil the power dissipated in it is 2 αP\sqrt2\,\alpha P. The value of α\alpha is .
    1. (1)36
    2. (2)1282128\sqrt2
    3. (3)16
    4. (4)64
    We corrected a printing error in the original paper

    Source printed “For a second coils number of turns”.

  14. Two identical long current carrying wires are bent into the shapes shown in the following figures. If the magnitude of magnetic fields at the centres P and Q of a semicircular arc are B1B_1 and B2B_2 respectively, then the ratio B1B2\dfrac{B_1}{B_2} is .
    1. (1)2+π1+π\dfrac{2+\pi}{1+\pi}
    2. (2)1+π1−π\dfrac{1+\pi}{1-\pi}
    3. (3)2+π1−π\dfrac{2+\pi}{1-\pi}
    4. (4)1+π2−π\dfrac{1+\pi}{2-\pi}
  15. Q15 · MCQ · Ray OpticsOpen
    For a thin symmetric prism made of glass (refractive index 1.5), the ratio of incident angle and minimum deviation will be .
    1. (1)3 : 4
    2. (2)3 : 2
    3. (3)2 : 1
    4. (4)1 : 2
  16. Q16 · MCQ · Ray OpticsOpen
    Refer the figure given below. μ1\mu_1 and μ2\mu_2 are refractive indices of air and lens material. The height of image will be cm.
    1. (1)1
    2. (2)0.5
    3. (3)1.2
    4. (4)0.25
  17. For a certain metal, when monochromatic light of wavelength λ\lambda is incident, the stopping potential for photoelectrons is 3V03V_0. When the same metal is illuminated by light of wavelength 2λ2\lambda, then the stopping potential becomes V0V_0. The threshold wavelength for photoelectric emission for the given metal is αλ\alpha\lambda. The value of α\alpha is .
    1. (1)1
    2. (2)4
    3. (3)2
    4. (4)3
  18. An electromagnetic wave travelling in x-direction is described by field equation Ey=300sin⁡ω(t−xc).E_y = 300\sin\omega\left(t - \frac{x}{c}\right). If the electron is restricted to move in y-direction only with speed of 1.5×1061.5\times10^{6} m/s then ratio of maximum electric and magnetic forces acting on the electron is .
    1. (1)200
    2. (2)150
    3. (3)400
    4. (4)300
  19. Q19 · MCQ · AtomsOpen
    Angular momentum of an electron in a hydrogen atom is 3hπ\dfrac{3h}{\pi}, then the energy of the electron is eV.
    1. (1)−1.51-1.51
    2. (2)−0.85-0.85
    3. (3)−0.38-0.38
    4. (4)−0.28-0.28
  20. A liquid drop of diameter 2 mm breaks into 512 droplets. The change in surface energy is α×10−6\alpha\times10^{-6} J. The value of α\alpha is . (Take surface tension of liquid =0.08= 0.08 N/m)
    1. (1)10
    2. (2)7
    3. (3)8
    4. (4)11
  21. Q21 · Numerical · Wave OpticsOpen
    In single slit diffraction pattern, the wavelength of light used is 628 nm and slit width is 0.2 mm, the angular width of central maximum is α×10−2\alpha\times10^{-2} degrees. The value of α\alpha is .
  22. Q22 · Numerical · ThermodynamicsOpen
    A vessel contains 0.15 m30.15\ \mathrm{m^3} of a gas at pressure 8 bar and temperature 140∘140^\circC with cp=3Rc_p = 3R and cv=2Rc_v = 2R. It is expanded adiabatically till pressure falls to 1 bar. The work done during this process is kJ. (RR is gas constant)
  23. 1 μ1\ \muC charge is moving with velocity v⃗=(i^−2j^+3k^)\vec v = \left(\hat i - 2\hat j + 3\hat k\right) m/s in the region of magnetic field B⃗=(2i^+3j^−5k^)\vec B = \left(2\hat i + 3\hat j - 5\hat k\right) T. The magnitude of force acting on it is α×10−6\sqrt\alpha\times10^{-6} N. The value of α\alpha is .
    We corrected a printing error in the original paper

    Source printed “1 μ1\ \muC charge moving with velocity” (no verb).

  24. A uniform wire of length ll of weight ww is suspended from the roof with a weight of WW at the other end. The stress in the wire at l3\dfrac{l}{3} distance from the top is (WA+2γwA)\left(\dfrac{W}{A} + \dfrac{2}{\gamma}\dfrac{w}{A}\right), where, AA is the cross sectional area of the wire. The value of γ\gamma is .
    We corrected a printing error in the original paper

    Answer corrected; the source key is (6) — it takes the weight of the wire below the point as w/3w/3, but at l/3l/3 from the top the wire below weighs 2w/32w/3, so the stress is W/A+23 w/AW/A + \frac{2}{3}\,w/A and γ=3\gamma = 3.

  25. A tube is filled with water and a wooden cube 10 cm×10 cm×10 cm10\ \mathrm{cm}\times10\ \mathrm{cm}\times10\ \mathrm{cm} is placed in the water. The wooden cube is found to float on the water with a part of it submerged in water. When a metal coin is placed on the wooden cube, the submerged part is increased by 3.87 cm. The mass of the metal coin is gram. (Take water density as 1 g/cm31\ \mathrm{g/cm^3} and density of wood as 0.4 g/cm30.4\ \mathrm{g/cm^3})

Chemistry

  1. The mass of iron converted into FeX3OX4\ce{Fe3O4} by the action of 18 g of steam is :

    (Given : Molar mass of H, O and Fe are 1, 16 and 56 g mol−1^{-1} respectively)

    Assume iron is present in excess :

    1. (1)2.1 g
    2. (2)4.2 g
    3. (3)21 g
    4. (4)42 g
  2. What is the energy (in J atom−1^{-1}) required for the following process ?

    LiX2+(g)→LiX3+(g)+eX−\ce{Li^2+(g) -> Li^3+(g) + e-}

    (Take the ionization energy for the H atom in the ground state as 2.18×10−182.18\times10^{-18} J atom−1^{-1})

    1. (1)8.72×10−188.72\times10^{-18}
    2. (2)1.962×10−181.962\times10^{-18}
    3. (3)1.962×10−171.962\times10^{-17}
    4. (4)6.54×10−176.54\times10^{-17}
  3. Given below are two statements :

    Statement (I) : The correct sequence of bond lengths in the following species is :

    OX2X+\ce{O2+} << OX2\ce{O2} << OX2X−\ce{O2-} << OX2X2−\ce{O2^2-}

    Statement (II) : The correct sequence of number of unpaired electrons in the following species is :

    OX2\ce{O2} >> OX2X+\ce{O2+} >> OX2X−\ce{O2-} >> OX2X2−\ce{O2^2-}

    In the light of the above statements, choose the correct answer from the options given below :

    1. (1)Both Statement I and Statement II are true
    2. (2)Both Statement I and Statement II are false
    3. (3)Statement I is true but Statement II is false
    4. (4)Statement I is false but Statement II is true
  4. Q4 · MCQ · ThermodynamicsOpen

    Consider the following data

    (i) 2 Al(s)+6 HCl(aq)→AlX2ClX6(aq)+3 HX2(g)\ce{2Al(s) + 6HCl(aq) -> Al2Cl6(aq) + 3H2(g)} + 1200 kJ/mol.

    (ii) HX2(g)+ClX2(g)→2 HCl(g)\ce{H2(g) + Cl2(g) -> 2HCl(g)} + 164 kJ/mol.

    (iii) HCl(g)+aq→HCl(aq)\ce{HCl(g) + aq -> HCl(aq)} + 83 kJ/mol.

    (iv) AlX2ClX6(s)+aq→AlX2ClX6(aq)\ce{Al2Cl6(s) + aq -> Al2Cl6(aq)} + 663 kJ/mol.

    The enthalpy of formation of anhydrous solid AlX2ClX6\ce{Al2Cl6} is :

    1. (1)−648-648 kJ mol−1^{-1}
    2. (2)−1350-1350 kJ mol−1^{-1}
    3. (3)−2002-2002 kJ mol−1^{-1}
    4. (4)−1527-1527 kJ mol−1^{-1}
  5. Q5 · MCQ · SolutionsOpen

    19.5 g of fluoro acetic acid (molar mass = 78 g mol−1^{-1}) is dissolved in 500g of water at 298 K. The depression in the freezing point of water was 1∘^\circC. What is KaK_\mathrm{a} of fluoro acetic acid ?

    (For water, Kf=1.86K_\mathrm{f} = 1.86 K kg mol−1^{-1}). Assume molarity and molality to have same values.

    1. (1)10−610^{-6}
    2. (2)4×10−44\times10^{-4}
    3. (3)3×10−53\times10^{-5}
    4. (4)3×10−33\times10^{-3}
  6. Q6 · MCQ · EquilibriumOpen

    The solubility product constants of AgX2CrOX4\ce{Ag2CrO4} and AgBr are 32x and 4y respectively at 298 K.

    The value of (molarity of AgX2CrOX4molarity of AgBr)\left(\dfrac{{\text{molarity of }\ce{Ag2CrO4}}}{\text{molarity of AgBr}}\right) can be expressed as :

    1. (1)2x3y\dfrac{2\sqrt[3]{\mathrm{x}}}{\mathrm{y}}
    2. (2)2xy2\sqrt{\dfrac{\mathrm{x}}{\mathrm{y}}}
    3. (3)xy\sqrt{\dfrac{\mathrm{x}}{\mathrm{y}}}
    4. (4)x3y\dfrac{\sqrt[3]{\mathrm{x}}}{\sqrt{\mathrm{y}}}
  7. An electrochemical cell is constructed using half cells in the direction of spontaneous change

    Fe(OH)X2(s)+2 eX−→Fe(s)+2 OHX−(aq)\ce{Fe(OH)2(s) + 2e- -> Fe(s) + 2OH-(aq)}   E0=−0.88E^0 = -0.88 V

    and AgBr(s)+eX−→Ag(s)+BrX−(aq)\ce{AgBr(s) + e- -> Ag(s) + Br-(aq)}   E0=+0.07E^0 = +0.07 V

    Which of the following option is correct ?

    1. (1)Overall reaction Fe(s)+2 OHX−1(aq)+2 AgBr(s)⇌Fe(OH)X2(s)+2 Ag(s)+2 BrX−(aq)\ce{Fe(s) + 2OH^{-1}(aq) + 2AgBr(s) <=> Fe(OH)2(s) + 2Ag(s) + 2Br-(aq)}
    2. (2)Ecell0=−0.95E^0_\mathrm{cell} = -0.95 V
    3. (3)Fe is reduced in the electrochemical cell
    4. (4)Ecell0E^0_\mathrm{cell} is an extensive property
  8. t100%t_{100\%} is the time required for the 100% completion of the reaction while t1/2t_{1/2} is the time required for 50% of the reaction to be completed. Which of the following option correctly represents the relation between t100%t_{100\%} and t1/2t_{1/2} for zero and first order reactions respectively ?
    1. (1)t100%=(t1/2)2t_{100\%} = (t_{1/2})^2 and t100%=(t1/2)−∞t_{100\%} = (t_{1/2})^{-\infty}
    2. (2)t100%=2t1/2t_{100\%} = 2t_{1/2} and t100%=(t1/2)∞t_{100\%} = (t_{1/2})^{\infty}
    3. (3)t100%=2t1/2t_{100\%} = 2t_{1/2} and t100%=(2t1/2)2t_{100\%} = (2t_{1/2})^2
    4. (4)t100%=(t1/2)∞t_{100\%} = (t_{1/2})^{\infty} and t100%=2t1/2t_{100\%} = 2t_{1/2}
  9. Given below are two statements :

    Statement (I) : The first ionisation enthalpy of the elements Na, Mg, Cl and Ar follows the order

    Na >> Mg >> Cl >> Ar

    Statement (II) : Among Ca, Al, Fe and B, the third ionisation enthalpy is very high for Ca.

    In the light of the above statements, choose the correct answer from the options given below :

    1. (1)Both Statement I and Statement II are true
    2. (2)Both Statement I and Statement II are false
    3. (3)Statement I is true but Statement II is false
    4. (4)Statement I is false but Statement II is true
  10. Q10 · MCQ · Redox ReactionsOpen

    Given below are two statements :

    Statement (I) : Oxidising power of halogens decreases in the order FX2\ce{F2} >> ClX2\ce{Cl2} >> BrX2\ce{Br2} >> IX2\ce{I2}, which is the basis of “Layer test”.

    Statement (II) : “Layer test” to identify BrX2\ce{Br2} and IX2\ce{I2} in aqueous solution involves the oxidation of bromide or iodide into BrX2\ce{Br2} or IX2\ce{I2} respectively with ClX2\ce{Cl2}, which is a type of displacement redox reaction.

    In the light of the above statements, choose the correct answer from the options given below :

    1. (1)Both Statement I and Statement II are true
    2. (2)Both Statement I and Statement II are false
    3. (3)Statement I is true but Statement II is false
    4. (4)Statement I is false but Statement II is true
  11. Q11 · MCQ · d- and f-BlockOpen
    Which of the following sets includes all the species that will change the orange colour of KX2CrX2OX7\ce{K2Cr2O7} in acidic medium ?
    1. (1)FeX2+\ce{Fe^2+}, SnX2+\ce{Sn^2+}, IX−\ce{I-}, SX2−\ce{S^2-}
    2. (2)SX2−\ce{S^2-}, FeX3+\ce{Fe^3+}, IX−\ce{I-}, CX2OX4X2−\ce{C2O4^2-}
    3. (3)FeX2+\ce{Fe^2+}, NOX2X−\ce{NO2-}, SOX2\ce{SO2}, SnX4+\ce{Sn^4+}
    4. (4)FeX3+\ce{Fe^3+}, SOX4X2−\ce{SO4^2-}, SX2−\ce{S^2-}, SnX4+\ce{Sn^4+}
  12. Match List – I with List – II.
    List – IList – II
    Chromium (III) ComplexesΔ0\boldsymbol{\Delta_0}(cm−1^{\mathbf{-1}})
    (en = ethylene diamine)
    A.[Cr(CN)X6]X3−\ce{[Cr(CN)6]^3-}I.15,060
    B.[CrFX6]X3−\ce{[CrF6]^3-}II.17,400
    C.[Cr(HX2O)X6]X3+\ce{[Cr(H2O)6]^3+}III.22,300
    D.[Cr(en)X3]X3+\ce{[Cr(en)3]^3+}IV.26,600
    Choose the correct answer from the options given below :
    1. (1)A-I, B-II, C-III, D-IV
    2. (2)A-II, B-III, C-IV, D-I
    3. (3)A-III, B-IV, C-I, D-II
    4. (4)A-IV, B-I, C-II, D-III
    We corrected a printing error in the original paper

    Source printed “[Cr(H2_2O)6_6)]3+^{3+}” (stray closing parenthesis).

  13. Given below are two statements :

    Statement (I) : 1,2,3-Trihydroxypropane can be separated from water by simple distillation.

    Statement (II) : An azeotropic mixture cannot be separated by fractional distillation.

    In the light of the above statements, choose the correct answer from the options given below :

    1. (1)Both Statement I and Statement II are true
    2. (2)Both Statement I and Statement II are false
    3. (3)Statement I is true but Statement II is false
    4. (4)Statement I is false but Statement II is true
    We corrected a printing error in the original paper

    Source printed “An azotropic mixture”.

  14. Given below are two statements :

    Statement (I) : Benzyl chloride reacts faster in SN_\mathrm{N}1 mechanism than ethyl chloride.

    Statement (II) : Ethyl carbocation intermediate is less stabilized by hyperconjugation than benzyl carbocation by resonance.

    In the light of the above statements, choose the correct answer from the options given below :

    1. (1)Both Statement I and Statement II are true
    2. (2)Both Statement I and Statement II are false
    3. (3)Statement I is true but Statement II is false
    4. (4)Statement I is false but Statement II is true
  15. In IUPAC nomenclature, the correct order of decreasing priority of functional group is :
    1. (1)−CONH2-\mathrm{CONH_2}, >C=O\mathord{>}\mathrm{C{=}O}, −CHO-\mathrm{CHO}, −NH2-\mathrm{NH_2}, −C≡C−-\mathrm{C{\equiv}C}-
    2. (2)−CONH2-\mathrm{CONH_2}, −COOCH3-\mathrm{COOCH_3}, −CHO-\mathrm{CHO}, −NH2-\mathrm{NH_2}, −OH-\mathrm{OH}
    3. (3)−CONH2-\mathrm{CONH_2}, −CHO-\mathrm{CHO}, >C=O\mathord{>}\mathrm{C{=}O}, −NH2-\mathrm{NH_2}, −C≡C−-\mathrm{C{\equiv}C}-
    4. (4)−CONH2-\mathrm{CONH_2}, −CHO-\mathrm{CHO}, −CN-\mathrm{CN}, −NH2-\mathrm{NH_2}, −C≡C−-\mathrm{C{\equiv}C}-
  16. Q16 · MCQ · HydrocarbonsOpen
    For the given molecule, “x”, the preferred site for the attack of the electrophile is :
    1. (1)Predominantly at “r”
    2. (2)“r” and “u”
    3. (3)“p” and “s”
    4. (4)Predominantly at “u”
  17. Match List-I with List-II.
    List-IList-II
    Mixture of CompoundsReagent used to distinguish
    A.Diethyl amine + Ethyl amineI.Bromine water
    B.Acetaldehyde + AcetoneII.CHClX3\ce{CHCl3} + KOH, Δ\Delta
    C.Ethanol + PhenolIII.Neutral FeClX3\ce{FeCl3}
    D.Benzoic acid + Cinnamic acidIV.Ammoniacal silver nitrate
    Choose the correct answer from the options given below :
    1. (1)A-IV, B-II, C-I, D-III
    2. (2)A-IV, B-II, C-III, D-I
    3. (3)A-II, B-IV, C-I, D-III
    4. (4)A-II, B-IV, C-III, D-I
    We corrected a printing error in the original paper

    Source printed “Ammonical silver nitrate”.

  18. Q18 · MCQ · AminesOpen
    Consider the three aromatic molecules (P, Q and R) whose structures have been given below :
    The correct order regarding the reactivity of these compounds with Ph−N(+)≡N  Cl(−)\mathrm{Ph{-}\underset{{\scriptstyle(+)}}{N}{\equiv}N\;Cl^{(-)}} under optimum but slightly acidic medium is :
    1. (1)P >> Q >> R
    2. (2)R >> P >> Q
    3. (3)R >> Q >> P
    4. (4)P >> R >> Q
  19. Q19 · MCQ · BiomoleculesOpen
    Match List-I with List-II.
    List-IList-II
    VitaminName
    A.Vitamin B1_1I.Pyridoxine
    B.Vitamin B2_2II.Ascorbic acid
    C.Vitamin B6_6III.Thiamine
    D.Vitamin CIV.Riboflavin
    Choose the correct answer from the options given below :
    1. (1)A-II, B-I, C-III, D-IV
    2. (2)A-IV, B-III, C-II, D-I
    3. (3)A-III, B-IV, C-I, D-II
    4. (4)A-I, B-III, C-II, D-IV
  20. A salt with few drops of conc. HCl gives apple green colour in flame test. The group precipitate of the salt is dissolved in acetic acid and treated with KX2CrOX4\ce{K2CrO4} to give yellow precipitate. When the sodium carbonate extract of the salt solution is heated with conc. HNOX3\ce{HNO3} and ammonium molybdate, it resulted in a canary yellow precipitate. The cation and anion present in the salt are respectively.
    1. (1)CaX2+\ce{Ca^2+} and SOX4X2−\ce{SO4^2-}
    2. (2)BaX2+\ce{Ba^2+} and POX4X3−\ce{PO4^3-}
    3. (3)MnX2+\ce{Mn^2+} and POX4X3−\ce{PO4^3-}
    4. (4)BaX2+\ce{Ba^2+} and SOX4X2−\ce{SO4^2-}
    We corrected a printing error in the original paper

    Source printed “it resulted a canary yellow precipitate”.

  21. Q21 · Numerical · Coordination CompoundsOpen

    5.33 g of CrClX3 ⋅ 6 HX2O\ce{CrCl3*6H2O}, which is a 1 : 3 electrolyte, is dissolved in water and is passed through a cation exchanger. The chloride ions in the eluted solution, on treatment with AgNOX3\ce{AgNO3} result in 8.61 g of AgCl. The ratio of moles of complex reacted and moles of AgCl formed is  ×10−2\times10^{-2}. (Nearest integer)

    [Molar mass in g mol−1^{-1} Cr : 52, Ag : 108, Cl : 35.5, H : 1, O : 16]

    We corrected a printing error in the original paper

    Source printed “The chloride ions … on treatment with AgNO3_3 results in”.

  22. Q22 · Numerical · HydrocarbonsOpen
    Consider the isomers of hydrocarbon with molecular formula CX5HX10\ce{C5H10}. These isomers do not decolourise KMnOX4\ce{KMnO4} solution. These isomers are subjected to chlorination with chlorine in presence of light to give monochloro compounds. The total number of monochloro compounds (structural isomers only) formed is .
  23. Q23 · Numerical · HydrocarbonsOpen
    One mole of an alkane (x) requires 8 mole oxygen for complete combustion. Sum of number of carbon and hydrogen atoms in the alkane (x) is .
  24. Q24 · Numerical · Chemical KineticsOpen

    For reaction A→P\ce{A -> P}, rate constant k=1.5×103k = 1.5\times10^{3} s−1^{-1} at 27∘^\circC. If activation energy for the above reaction is 60 kJ mol−1^{-1}, then the temperature (in ∘^\circC) at which rate constant, k=4.5×103k = 4.5\times10^{3} s−1^{-1} is . (Nearest integer)

    Given : log⁡2=0.30\log 2 = 0.30, log⁡3=0.48\log 3 = 0.48, R=8.3R = 8.3 J K−1^{-1} mol−1^{-1}, ln⁡10=2.3\ln 10 = 2.3

  25. Q25 · Numerical · ThermodynamicsOpen
    At the transition temperature T, A⇌B\ce{A <=> B} and ΔG0=105−35log⁡T\Delta G^0 = 105 - 35\log T where A and B are two states of substance X. The transition temperature in ∘^\circC when pressure is 1 atm is . (Nearest integer)

Maths

  1. Let α,α+2\alpha, \alpha + 2, α∈Z\alpha \in \mathbb{Z}, be the roots of the quadratic equation x(x+2)+(x+1)(x+3)+(x+2)(x+4)+…+(x+n−1)(x+n+1)=4nx(x+2) + (x+1)(x+3) + (x+2)(x+4) + \ldots + (x+n-1)(x+n+1) = 4n for some n∈Nn \in \mathbb{N}. Then (n+α)(n + \alpha) is equal to:
    1. (1)0
    2. (2)1
    3. (3)2
    4. (4)3
  2. Let xx and yy be real numbers such that 50(2x1+3i−y1−2i)=31+17i,i=−1.50\left(\dfrac{2x}{1+3i} - \dfrac{y}{1-2i}\right) = 31 + 17i,\quad i = \sqrt{-1}. Then the value of 10(x−3y)10(x - 3y) is:
    1. (1)20
    2. (2)31
    3. (3)35
    4. (4)75
    We corrected a printing error in the original paper

    Source printed “Let xx and yy be real number”.

  3. Let α,β∈R\alpha, \beta \in \mathbb{R} be such that the system of linear equations
    x+2y+z=52x+y+αz=58x+4y+βz=18\begin{align*} x + 2y + z &= 5\\ 2x + y + \alpha z &= 5\\ 8x + 4y + \beta z &= 18 \end{align*}
    has no solution. Then βα\dfrac{\beta}{\alpha} is equal to:
    1. (1)−4-4
    2. (2)4
    3. (3)8
    4. (4)−8-8
  4. Let A=[121α]A = \begin{bmatrix} 1 & 2\\ 1 & \alpha\end{bmatrix} and B=[33β2]B = \begin{bmatrix} 3 & 3\\ \beta & 2\end{bmatrix}. If A2−4A+I=OA^2 - 4A + I = O and B2−5B−6I=OB^2 - 5B - 6I = O, then among the two statements:
    • (S1):[(B−A)(B+A)]T=[1315710][(B - A)(B + A)]^{T} = \begin{bmatrix} 13 & 15\\ 7 & 10\end{bmatrix}
    and
    • (S2):det⁡(adj⁡(A+B))=−5\det(\operatorname{adj}(A + B)) = -5,
    1. (1)only (S1) is correct
    2. (2)only (S2) is correct
    3. (3)both (S1) and (S2) are correct
    4. (4)both (S1) and (S2) are wrong
  5. Let AA be the set of first 101 terms of an A.P., whose first term is 1 and the common difference is 5 and let BB be the set of first 71 terms of an A.P., whose first term is 9 and the common difference is 7. Then the number of elements in A∩BA \cap B, which are divisible by 3, is:
    1. (1)4
    2. (2)5
    3. (3)6
    4. (4)7
    We corrected a printing error in the original paper

    Source printed “the number of elements is A∩BA \cap B”.

  6. The number of seven-digit numbers, that can be formed by using the digits 1, 2, 3, 5 and 7 such that each digit is used at least once, is;
    1. (1)15400
    2. (2)17800
    3. (3)16800
    4. (4)29400
  7. The number of elements in the set S={(r,k):k∈Z and 36Cr+1=6(35Cr)(k2−3)},S = \left\{(r, k) : k \in \mathbb{Z} \text{ and } {}^{36}C_{r+1} = \dfrac{6\left({}^{35}C_r\right)}{(k^2 - 3)}\right\}, is
    1. (1)2
    2. (2)4
    3. (3)8
    4. (4)16
  8. Q8 · MCQ · StatisticsOpen
    If the mean of the data
    Class5-1010-1515-2020-2525-3030-35
    Frequency2kk2854k+1k+15
    is 21, then kk is one of the roots of the equation:
    1. (1)2x2−23x−10=02x^2 - 23x - 10 = 0
    2. (2)4x2−35x+24=04x^2 - 35x + 24 = 0
    3. (3)2x2−19x−10=02x^2 - 19x - 10 = 0
    4. (4)2x2−35x+98=02x^2 - 35x + 98 = 0
  9. Q9 · MCQ · Straight LinesOpen
    Let the mid points of the sides of a triangle ABCABC be (52,7)\left(\dfrac52, 7\right), (52,3)\left(\dfrac52, 3\right) and (4,5)(4, 5). If its incentre is (h,k)(h, k), then 3h+k3h + k is equal to:
    1. (1)11
    2. (2)12
    3. (3)13
    4. (4)14
  10. Q10 · MCQ · Conic SectionsOpen
    Let an ellipse x2a2+y2b2=1\dfrac{x^2}{a^2} + \dfrac{y^2}{b^2} = 1, a<ba < b, pass through the point (4,3)(4, 3) and have eccentricity 53\dfrac{\sqrt5}{3}. Then the length of its latus rectum is:
    1. (1)453\dfrac{4\sqrt5}{3}
    2. (2)252\sqrt5
    3. (3)753\dfrac{7\sqrt5}{3}
    4. (4)853\dfrac{8\sqrt5}{3}
  11. Q11 · MCQ · TrigonometryOpen
    If sin⁡(π18)sin⁡(5π18)sin⁡(7π18)=K\sin\left(\dfrac{\pi}{18}\right)\sin\left(\dfrac{5\pi}{18}\right)\sin\left(\dfrac{7\pi}{18}\right) = K, then the value of sin⁡(10Kπ3)\sin\left(\dfrac{10K\pi}{3}\right) is:
    1. (1)3+122\dfrac{\sqrt3 + 1}{2\sqrt2}
    2. (2)3−12\dfrac{\sqrt3 - 1}{\sqrt2}
    3. (3)32\dfrac{\sqrt3}{2}
    4. (4)12\dfrac12
  12. Q12 · MCQ · TrigonometryOpen
    Let S={x∈[−π,π]:sin⁡x (sin⁡x+cos⁡x)=a, a∈Z}S = \{x \in [-\pi, \pi] : \sin x\,(\sin x + \cos x) = a,\ a \in \mathbb{Z}\}. Then n(S)n(S) is equal to:
    1. (1)3
    2. (2)6
    3. (3)7
    4. (4)9
  13. Q13 · MCQ · 3D GeometryOpen
    If the point of intersection of the lines x+13=y+a5=z+b+17\dfrac{x+1}{3} = \dfrac{y+a}{5} = \dfrac{z+b+1}{7} and x−21=y−b4=z−2a7\dfrac{x-2}{1} = \dfrac{y-b}{4} = \dfrac{z-2a}{7} lies on xy-plane, then the value of a+ba + b is:
    1. (1)2
    2. (2)5
    3. (3)7
    4. (4)9
  14. Q14 · MCQ · VectorsOpen
    If a⃗\vec a and b⃗\vec b are two vectors such that ∣a⃗∣=2\lvert\vec a\rvert = 2 and ∣b⃗∣=3\lvert\vec b\rvert = 3, then the maximum value of 3∣(3a⃗+2b⃗)∣+4∣(3a⃗−2b⃗)∣3\left\lvert\left(3\vec a + 2\vec b\right)\right\rvert + 4\left\lvert\left(3\vec a - 2\vec b\right)\right\rvert is:
    1. (1)30
    2. (2)36
    3. (3)60
    4. (4)72
  15. Q15 · MCQ · 3D GeometryOpen
    Let a line LL passing through the point (1,1,1)(1, 1, 1) be perpendicular to both the vectors 2i^+2j^+k^2\hat i + 2\hat j + \hat k and i^+2j^+2k^\hat i + 2\hat j + 2\hat k. If P(a,b,c)P(a, b, c) is the foot of perpendicular from the origin on the line LL, then the value of 34(a+b+c)34(a + b + c) is:
    1. (1)50
    2. (2)80
    3. (3)100
    4. (4)120
    We corrected a printing error in the original paper

    Source printed the second vector as “i^+2j^+k^\hat i + 2\hat j + \hat k”; corrected to the intended “i^+2j^+2k^\hat i + 2\hat j + 2\hat k” (the source's own solution uses it; as printed 34(a+b+c)=95.234(a+b+c) = 95.2, no option).

  16. If lim⁡x→2sin⁡(x3−5x2+ax+b)(x−1−1)log⁡e(x−1)=m\displaystyle\lim_{x\to2}\frac{\sin\left(x^3 - 5x^2 + ax + b\right)}{\left(\sqrt{x-1} - 1\right)\log_e(x-1)} = m, then a+b+ma + b + m is equal to:
    1. (1)5
    2. (2)6
    3. (3)8
    4. (4)10
  17. If the curve y=f(x)y = f(x) passes through the point (1,e)(1, e) and satisfies the differential equation dy=y (2+log⁡ex) dxdy = y\,(2 + \log_e x)\,dx, x>0x > 0, then f(e)f(e) is equal to:
    1. (1)eee^{e}
    2. (2)ee2e^{e^2}
    3. (3)e2ee^{2e}
    4. (4)e2ee^{2^e}
  18. The number of critical points of the function f(x)={∣sin⁡xx∣,x≠01,x=0f(x) = \begin{cases} \left\lvert\dfrac{\sin x}{x}\right\rvert, & x \neq 0\\[6pt] 1, & x = 0\end{cases} in the interval (−2π,2π)(-2\pi, 2\pi) is equal to:
    1. (1)1
    2. (2)3
    3. (3)5
    4. (4)7
  19. Let [⋅][\cdot] denote the greatest integer function. Then the value of ∫03(ex+e−x[x]!)dx\displaystyle\int_0^3\left(\frac{e^x + e^{-x}}{[x]!}\right)dx is:
    1. (1)e2+e3−1e2−1e3e^2 + e^3 - \dfrac{1}{e^2} - \dfrac{1}{e^3}
    2. (2)12(e2+e3−1e2−1e3)\dfrac12\left(e^2 + e^3 - \dfrac{1}{e^2} - \dfrac{1}{e^3}\right)
    3. (3)e2+e3−12e2−12e3e^2 + e^3 - \dfrac{1}{2e^2} - \dfrac{1}{2e^3}
    4. (4)12(e2+e3)−1e2−1e3\dfrac12(e^2 + e^3) - \dfrac{1}{e^2} - \dfrac{1}{e^3}
  20. Let y=y(x)y = y(x) be the solution curve of the differential equation (1+sin⁡x)dydx+(y+1)cos⁡x=0(1 + \sin x)\dfrac{dy}{dx} + (y + 1)\cos x = 0, y(0)=0y(0) = 0. If the curve y=y(x)y = y(x) passes through the point (α,−12)\left(\alpha, \dfrac{-1}{2}\right), then a value of α\alpha is:
    1. (1)π6\dfrac{\pi}{6}
    2. (2)π4\dfrac{\pi}{4}
    3. (3)π3\dfrac{\pi}{3}
    4. (4)π2\dfrac{\pi}{2}
  21. If the domain of the function f(x)=log⁡(0.6)(∣2x−5x2−4∣)f(x) = \sqrt{\log_{(0.6)}\left(\left\lvert\dfrac{2x-5}{x^2-4}\right\rvert\right)} is (−∞,a]∪{b}∪[c,d)∪(e,∞)(-\infty, a] \cup \{b\} \cup [c, d) \cup (e, \infty), then the value of a+b+c+d+ea + b + c + d + e is .
  22. Q22 · Numerical · Sequences & SeriesOpen
    If ∑k=1nak=6n3\displaystyle\sum_{k=1}^{n} a_k = 6n^3, then ∑k=16(ak+1−ak36)2\displaystyle\sum_{k=1}^{6}\left(\frac{a_{k+1} - a_k}{36}\right)^2 is equal to .
  23. Q23 · Numerical · ProbabilityOpen
    Let a,b,c∈{1,2,3,4}a, b, c \in \{1, 2, 3, 4\}. If the probability, that ax2+22 bx+c>0ax^2 + 2\sqrt2\,bx + c > 0 for all x∈Rx \in \mathbb{R}, is mn\dfrac{m}{n}, gcd⁡(m,n)=1\gcd(m, n) = 1, then m+nm + n is equal to .
  24. Q24 · Numerical · CirclesOpen
    Let a circle CC have its centre in the first quadrant, intersect the coordinate axes at exactly three points and cut off equal intercepts from the coordinate axes. If the length of the chord of CC on the line x+y=1x + y = 1 is 14\sqrt{14}, then the square of the radius of CC is .
  25. Q25 · Numerical · Definite IntegrationOpen
    If α=∫023log⁡2(x2+4)dx+∫242x−4 dx\alpha = \displaystyle\int_0^{2\sqrt3}\log_2\left(x^2 + 4\right)dx + \int_2^4\sqrt{2^x - 4}\,dx, then α2\alpha^2 is equal to .