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MathsJEE Main 2 Apr 2026, Shift 1·Q10·MCQ·Easy–moderate

Conic Sections · Ellipse latus rectum

Let an ellipse x2a2+y2b2=1\dfrac{x^2}{a^2} + \dfrac{y^2}{b^2} = 1, a<ba < b, pass through the point (4,3)(4, 3) and have eccentricity 53\dfrac{\sqrt5}{3}. Then the length of its latus rectum is:
  1. (1)453\dfrac{4\sqrt5}{3}
  2. (2)252\sqrt5
  3. (3)753\dfrac{7\sqrt5}{3}
  4. (4)853\dfrac{8\sqrt5}{3}

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