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PhysicsJEE Main 2 Apr 2026, Shift 1·Q6·MCQ·Easy–moderate

Rotational Motion · Rotational kinematics and torque

A particle is rotating in a circular path and at any instant its motion can be described as θ=5t440−t33\theta = \dfrac{5t^4}{40} - \dfrac{t^3}{3}. The angular acceleration of the particle after 10 seconds is rad/s2\mathrm{rad/s^2}.
  1. (1)150
  2. (2)120
  3. (3)130
  4. (4)170

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