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PhysicsJEE Main 2 Apr 2026, Shift 2·Q19·MCQ·Easy–moderate

Nuclei · Nuclear structure

The binding energy per nucleon of  83209Bi^{209}_{\ 83}\mathrm{Bi} is MeV. [Take m( 83209Bi)=208.980388m\left(^{209}_{\ 83}\mathrm{Bi}\right) = 208.980388 u, mp=1.007825m_p = 1.007825 u, mn=1.008665m_n = 1.008665 u, 1 u=931 MeV/c21\,\mathrm{u} = 931\ \mathrm{MeV}/c^2]
  1. (1)7.48
  2. (2)7.84
  3. (3)8.79
  4. (4)6.94

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