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MathsJEE Main 21 Jan 2026, Shift 2·Q12·MCQ·Easy–moderate

Sequences & Series · Geometric progression

Let a1,a22,a322,…,a1029a_1, \dfrac{a_2}{2}, \dfrac{a_3}{2^2}, \ldots, \dfrac{a_{10}}{2^9} be a G.P. of common ratio 12\dfrac{1}{\sqrt2}. If a1+a2+…+a10=62a_1 + a_2 + \ldots + a_{10} = 62, then a1a_1 is equal to:
  1. (1)2(2−1)2\left(\sqrt2 - 1\right)
  2. (2)2−22 - \sqrt2
  3. (3)2−1\sqrt2 - 1
  4. (4)2(2−2)2(2 - \sqrt2)

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