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Sequences & Series

31 JEE Main questions · Maths

  1. MathsJEE Main 21 Jan 2026, Shift 1·Q6·MCQ·Moderate
    Open

    Geometric progression

    Let a1,a2,a3,…a_1, a_2, a_3, \ldots be a G.P. of increasing positive terms such that a2⋅a3⋅a4=64a_2\cdot a_3\cdot a_4 = 64 and a1+a3+a5=8137a_1 + a_3 + a_5 = \dfrac{813}{7}. Then a3+a5+a7a_3 + a_5 + a_7 is equal to:
    1. (1)3256
    2. (2)3252
    3. (3)3244
    4. (4)3248
  2. MathsJEE Main 21 Jan 2026, Shift 1·Q22·Numerical·Tough
    Open

    Recursive sequence and series sum

    Let a1=1a_1 = 1 and for n≥1n \ge 1, an+1=12an+n2−2n−1n2(n+1)2a_{n+1} = \dfrac12 a_n + \dfrac{n^2 - 2n - 1}{n^2(n+1)^2}. Then ∣∑n=1∞(an−2n2)∣\left\lvert\displaystyle\sum_{n=1}^{\infty}\left(a_n - \frac{2}{n^2}\right)\right\rvert is equal to .
  3. MathsJEE Main 21 Jan 2026, Shift 2·Q1·MCQ·Moderate
    Open

    Sum of a finite series

    The positive integer nn, for which the solutions of the equation x(x+2)+(x+2)(x+4)+…+(x+2n−2)(x+2n)=8n3x(x+2) + (x+2)(x+4) + \ldots + (x+2n-2)(x+2n) = \dfrac{8n}{3} are two consecutive even integers, is:
    1. (1)3
    2. (2)6
    3. (3)12
    4. (4)9
  4. MathsJEE Main 21 Jan 2026, Shift 2·Q12·MCQ·Easy–moderate
    Open

    Geometric progression

    Let a1,a22,a322,…,a1029a_1, \dfrac{a_2}{2}, \dfrac{a_3}{2^2}, \ldots, \dfrac{a_{10}}{2^9} be a G.P. of common ratio 12\dfrac{1}{\sqrt2}. If a1+a2+…+a10=62a_1 + a_2 + \ldots + a_{10} = 62, then a1a_1 is equal to:
    1. (1)2(2−1)2\left(\sqrt2 - 1\right)
    2. (2)2−22 - \sqrt2
    3. (3)2−1\sqrt2 - 1
    4. (4)2(2−2)2(2 - \sqrt2)
  5. MathsJEE Main 22 Jan 2026, Shift 1·Q20·MCQ·Easy–moderate
    Open

    Arithmetic progression sums

    If the sum of the first four terms of an A.P. is 6 and the sum of its first six terms is 4, then the sum of its first twelve terms is
    1. (1)−20-20
    2. (2)−24-24
    3. (3)−26-26
    4. (4)−22-22
  6. MathsJEE Main 22 Jan 2026, Shift 2·Q24·Numerical·Moderate
    Open

    Arithmetic and geometric progressions

    Suppose a,b,ca, b, c are in A.P. and a2,2b2,c2a^2, 2b^2, c^2 are in G.P. If a<b<ca < b < c and a+b+c=1a + b + c = 1, then 9(a2+b2+c2)9(a^2 + b^2 + c^2) is equal to .
  7. MathsJEE Main 23 Jan 2026, Shift 2·Q20·MCQ·Easy–moderate
    Open

    Nth term from sum

    Let ∑k=1nak=αn2+βn\displaystyle\sum_{k=1}^{n} a_k = \alpha n^2 + \beta n. If a10=59a_{10} = 59 and a6=7a1a_6 = 7a_1 then α+β\alpha + \beta is equal to
    1. (1)12
    2. (2)3
    3. (3)5
    4. (4)7
  8. MathsJEE Main 24 Jan 2026, Shift 1·Q4·MCQ·Moderate
    Open

    Geometric progression sum

    Let 729,81,9,1,…729, 81, 9, 1, \ldots be a sequence and PnP_n denote the product of the first nn terms of this sequence. If 2∑n=140(Pn)1n=3α−13β2\sum_{n=1}^{40}\left(P_n\right)^{\frac1n} = \dfrac{3^{\alpha} - 1}{3^{\beta}} and gcd⁡(α,β)=1\gcd(\alpha, \beta) = 1, then α+β\alpha + \beta is equal to
    1. (1)73
    2. (2)74
    3. (3)75
    4. (4)76
  9. MathsJEE Main 24 Jan 2026, Shift 1·Q15·MCQ·Moderate
    Open

    Arithmetic progression sum

    Consider an A.P.: a1,a2,…,ana_1, a_2, \ldots, a_n; a1>0a_1 > 0. If a2−a1=−34a_2 - a_1 = \dfrac{-3}{4}, an=14a1a_n = \dfrac14 a_1, and ∑i=1nai=5252\displaystyle\sum_{i=1}^{n} a_i = \dfrac{525}{2}, then ∑i=117ai\displaystyle\sum_{i=1}^{17} a_i is equal to
    1. (1)476
    2. (2)952
    3. (3)238
    4. (4)136
  10. MathsJEE Main 24 Jan 2026, Shift 2·Q5·MCQ·Moderate
    Open

    Arithmetic progression

    Let α1,α2,α3,α4\alpha_1, \alpha_2, \alpha_3, \alpha_4 be an A.P. of four terms such that each term of the A.P. and its common difference ll are integers. If α1+α2+α3+α4=48\alpha_1 + \alpha_2 + \alpha_3 + \alpha_4 = 48 and α1α2α3α4+l4=361\alpha_1\alpha_2\alpha_3\alpha_4 + l^4 = 361 then the largest term of the A.P. is equal to
    1. (1)27
    2. (2)24
    3. (3)21
    4. (4)23
    We corrected a printing error in the original paper

    Source printed “α1,α2,α3,α4+l4=361\alpha_1, \alpha_2, \alpha_3, \alpha_4 + l^4 = 361” (commas instead of the product α1α2α3α4\alpha_1\alpha_2\alpha_3\alpha_4).

  11. MathsJEE Main 24 Jan 2026, Shift 2·Q7·MCQ·Moderate
    Open

    Infinite geometric series

    (13+47)+(132+13×47+4272)+(133+132×47+13×4272+4373)+…\left(\frac13 + \frac47\right) + \left(\frac{1}{3^2} + \frac13\times\frac47 + \frac{4^2}{7^2}\right) + \left(\frac{1}{3^3} + \frac{1}{3^2}\times\frac47 + \frac13\times\frac{4^2}{7^2} + \frac{4^3}{7^3}\right) + \ldots upto infinite terms is equal to
    1. (1)52\dfrac52
    2. (2)74\dfrac74
    3. (3)43\dfrac43
    4. (4)65\dfrac65
  12. MathsJEE Main 28 Jan 2026, Shift 1·Q2·MCQ·Moderate
    Open

    Exponential series sum

    The value of ∑k=1∞(−1)k+1(k(k+1)k!)\displaystyle\sum_{k=1}^{\infty}(-1)^{k+1}\left(\frac{k(k+1)}{k!}\right) is:
    1. (1)2/e2/e
    2. (2)1/e1/e
    3. (3)e\sqrt{e}
    4. (4)e/2e/2
  13. MathsJEE Main 28 Jan 2026, Shift 1·Q17·MCQ·Easy–moderate
    Open

    Arithmetic progression

    The common difference of the A.P.: a1,a2,…,ama_1, a_2, \ldots, a_m is 13 more than the common difference of the A.P.: b1,b2,…,bnb_1, b_2, \ldots, b_n. If b31=−277b_{31} = -277, b43=−385b_{43} = -385 and a78=327a_{78} = 327, then a1a_1 is equal to
    1. (1)21
    2. (2)24
    3. (3)19
    4. (4)16
  14. MathsJEE Main 28 Jan 2026, Shift 1·Q21·Numerical·Moderate
    Open

    Geometric progression

    In a G.P., if the product of the first three terms is 27 and the set of all possible values for the sum of its first three terms is R−(a,b)\mathbb{R} - (a, b), then a2+b2a^2 + b^2 is equal to .
  15. MathsJEE Main 28 Jan 2026, Shift 2·Q20·MCQ·Easy–moderate
    Open

    Sum of geometric progression

    6326+10⋅1325+10⋅2324+10⋅22323+⋯+10⋅2243\dfrac{6}{3^{26}} + \dfrac{10\cdot1}{3^{25}} + \dfrac{10\cdot2}{3^{24}} + \dfrac{10\cdot2^2}{3^{23}} + \cdots + \dfrac{10\cdot2^{24}}{3} is equal to
    1. (1)2252^{25}
    2. (2)2262^{26}
    3. (3)3253^{25}
    4. (4)3263^{26}
  16. MathsJEE Main 28 Jan 2026, Shift 2·Q21·Numerical·Moderate
    Open

    Telescoping series sum

    If ∑r=125(rr4+r2+1)=pq\displaystyle\sum_{r=1}^{25}\left(\frac{r}{r^4 + r^2 + 1}\right) = \frac{p}{q}, where pp and qq are positive integers such that gcd⁡(p,q)=1\gcd(p, q) = 1, then p+qp + q is equal to .
  17. MathsJEE Main 2 Apr 2026, Shift 1·Q5·MCQ·Moderate
    Open

    Common terms of two arithmetic progressions

    Let AA be the set of first 101 terms of an A.P., whose first term is 1 and the common difference is 5 and let BB be the set of first 71 terms of an A.P., whose first term is 9 and the common difference is 7. Then the number of elements in A∩BA \cap B, which are divisible by 3, is:
    1. (1)4
    2. (2)5
    3. (3)6
    4. (4)7
    We corrected a printing error in the original paper

    Source printed “the number of elements is A∩BA \cap B”.

  18. MathsJEE Main 2 Apr 2026, Shift 1·Q22·Numerical·Easy–moderate
    Open

    General term from partial sums

    If ∑k=1nak=6n3\displaystyle\sum_{k=1}^{n} a_k = 6n^3, then ∑k=16(ak+1−ak36)2\displaystyle\sum_{k=1}^{6}\left(\frac{a_{k+1} - a_k}{36}\right)^2 is equal to .
  19. MathsJEE Main 2 Apr 2026, Shift 2·Q4·MCQ·Easy–moderate
    Open

    Arithmetic and geometric progressions

    Let a1,a2,a3,…a_1, a_2, a_3, \ldots be an A.P. and g1=a1,g2,g3,…g_1 = a_1, g_2, g_3, \ldots be an increasing G.P. If a1=a2+g2=1a_1 = a_2 + g_2 = 1 and a3+g3=4a_3 + g_3 = 4, then a10+g5a_{10} + g_5 is equal to:
    1. (1)81
    2. (2)76
    3. (3)62
    4. (4)55
  20. MathsJEE Main 2 Apr 2026, Shift 2·Q5·MCQ·Moderate
    Open

    Sum of special series

    The sum 131+13+231+3+13+23+331+3+5+…\dfrac{1^3}{1} + \dfrac{1^3 + 2^3}{1 + 3} + \dfrac{1^3 + 2^3 + 3^3}{1 + 3 + 5} + \ldots up to 8 terms, is:
    1. (1)70
    2. (2)71
    3. (3)72
    4. (4)73
  21. MathsJEE Main 4 Apr 2026, Shift 1·Q7·MCQ·Moderate
    Open

    Arithmetic progression sum

    The first term of an A.P. of 30 non-negative terms is 103\dfrac{10}{3}. If the sum of this A.P. is the cube of its last term, then its common difference is:
    1. (1)587\dfrac{5}{87}
    2. (2)2583\dfrac{25}{83}
    3. (3)1529\dfrac{15}{29}
    4. (4)529\dfrac{5}{29}
  22. MathsJEE Main 4 Apr 2026, Shift 2·Q7·MCQ·Easy–moderate
    Open

    Infinite geometric series

    Let α=14+18+116+…∞\alpha = \dfrac14 + \dfrac18 + \dfrac1{16} + \ldots\infty and β=13+19+127+…∞\beta = \dfrac13 + \dfrac19 + \dfrac1{27} + \ldots\infty. Then the value of (0.2)log⁡5(α)+(0.04)log⁡5(β)(0.2)^{\log_{\sqrt5}(\alpha)} + (0.04)^{\log_5(\beta)} is equal to:
    1. (1)4
    2. (2)5
    3. (3)8
    4. (4)25
  23. MathsJEE Main 5 Apr 2026, Shift 1·Q2·MCQ·Easy–moderate
    Open

    Arithmetic progression sum of squares

    Let the sum of the first nn terms of an A.P. be 3n2+5n3n^2 + 5n. Then the sum of squares of the first 10 terms of the A.P. is:
    1. (1)10220
    2. (2)12860
    3. (3)15220
    4. (4)19780
  24. MathsJEE Main 5 Apr 2026, Shift 1·Q5·MCQ·Easy–moderate
    Open

    Telescoping series sum

    ∑n=110(528n(n+1)(n+2))\displaystyle\sum_{n=1}^{10}\left(\frac{528}{n(n+1)(n+2)}\right) is equal to:
    1. (1)65
    2. (2)130
    3. (3)220
    4. (4)440
  25. MathsJEE Main 5 Apr 2026, Shift 2·Q5·MCQ·Moderate
    Open

    Telescoping series sum

    If the sum of the first 10 terms of the series 11+14×4+21+24×4+31+34×4+41+44×4+…\frac{1}{1 + 1^4\times4} + \frac{2}{1 + 2^4\times4} + \frac{3}{1 + 3^4\times4} + \frac{4}{1 + 4^4\times4} + \ldots is mn\dfrac{m}{n}, gcd⁡(m,n)=1\gcd(m, n) = 1, then m+nm + n is equal to:
    1. (1)256
    2. (2)264
    3. (3)276
    4. (4)284
  26. MathsJEE Main 5 Apr 2026, Shift 2·Q6·MCQ·Easy–moderate
    Open

    Arithmetic means

    Let A1,A2,A3,…,A39A_1, A_2, A_3, \ldots, A_{39} be 39 arithmetic means between the numbers 59 and 159. Then the mean of A25A_{25}, A28A_{28}, A31A_{31} and A36A_{36} is equal to:
    1. (1)129
    2. (2)136
    3. (3)131.50
    4. (4)134
  27. MathsJEE Main 6 Apr 2026, Shift 1·Q5·MCQ·Easy–moderate
    Open

    Alternating sum of cubes

    The value of 13−23+33−…+1531^3 - 2^3 + 3^3 - \ldots + 15^3 is:
    1. (1)1706
    2. (2)1856
    3. (3)1982
    4. (4)2403
  28. MathsJEE Main 6 Apr 2026, Shift 1·Q6·MCQ·Moderate
    Open

    Arithmetic and geometric progressions

    The sum of the first ten terms of an A.P. is 160 and the sum of the first two terms of a G.P. is 8. If the first term of the A.P. is equal to the common ratio of the G.P. and the first term of the G.P. is equal to common difference of the A.P., then the sum of all possible values of the first term of the G.P. is:
    1. (1)349\dfrac{34}{9}
    2. (2)3413\dfrac{34}{13}
    3. (3)329\dfrac{32}{9}
    4. (4)3213\dfrac{32}{13}
  29. MathsJEE Main 6 Apr 2026, Shift 2·Q2·MCQ·Moderate
    Open

    Sum of geometric progression

    Consider the quadratic equation (n2−2n+2)x2−3x+(n2−2n+2)2=0(n^2 - 2n + 2)x^2 - 3x + (n^2 - 2n + 2)^2 = 0, n∈Rn \in \mathbb{R}. Let α\alpha be the minimum value of the product of its roots and β\beta be the maximum value of the sum of its roots. Then the sum of the first six terms of the G.P., whose first term is α\alpha and the common ratio is αβ\dfrac{\alpha}{\beta}, is:
    1. (1)6137\dfrac{61}{37}
    2. (2)12181\dfrac{121}{81}
    3. (3)364243\dfrac{364}{243}
    4. (4)1093729\dfrac{1093}{729}
  30. MathsJEE Main 6 Apr 2026, Shift 2·Q6·MCQ·Easy–moderate
    Open

    Sum of special series

    The sum 1+12(12+22)+13(12+22+32)+…1 + \dfrac12\left(1^2 + 2^2\right) + \dfrac13\left(1^2 + 2^2 + 3^2\right) + \ldots upto 10 terms is equal to:
    1. (1)130
    2. (2)155
    3. (3)3152\dfrac{315}{2}
    4. (4)3252\dfrac{325}{2}
  31. MathsJEE Main 8 Apr 2026, Shift 2·Q5·MCQ·Moderate
    Open

    Sum of arithmetic progressions

    Let α=3+4+8+9+13+14+…\alpha = 3 + 4 + 8 + 9 + 13 + 14 + \ldots upto 40 terms. If (tan⁡β)α1020(\tan\beta)^{\frac{\alpha}{1020}} is a root of the equation x2+x−2=0x^2 + x - 2 = 0, β∈(0,π2)\beta \in \left(0, \dfrac{\pi}{2}\right), then sin⁡2β+3cos⁡2β\sin^2\beta + 3\cos^2\beta is equal to:
    1. (1)2
    2. (2)74\dfrac74
    3. (3)52\dfrac52
    4. (4)32\dfrac32