MathsJEE Main 21 Jan 2026, Shift 2·Q16·MCQ·Moderate

Differential Equations · Linear differential equations

Let

y = y(x)

be the solution of the differential equation

\sec x\dfrac{dy}{dx} - 2y = 2 + 3\sin x

,

x \in \left(-\dfrac{\pi}{2}, \dfrac{\pi}{2}\right)

,

y(0) = -\dfrac{7}{4}

. Then

y\left(\dfrac{\pi}{6}\right)

is equal to:

(1) $-\dfrac{5}{2}$
(2) $-\dfrac{5}{4}$
(3) $-3\sqrt3 - 7$
(4) $-3\sqrt2 - 7$

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