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MathsJEE Main 24 Jan 2026, Shift 2·Q16·MCQ·Moderate

Differential Equations · Linear differential equations

Let y=y(x)y = y(x) be a differentiable function in the interval (0,∞)(0, \infty) such that y(1)=2y(1) = 2. and lim⁡t→x(t2y(x)−x2y(t)x−t)=3for each x>0.\lim_{t\to x}\left(\frac{t^2y(x) - x^2y(t)}{x - t}\right) = 3 \quad\text{for each } x > 0. Then 2y(2)2y(2) is equal to
  1. (1)18
  2. (2)23
  3. (3)27
  4. (4)12

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