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MathsJEE Main 22 Jan 2026, Shift 1·Q5·MCQ·Easy–moderate

Applications of Derivatives · Absolute minimum on an interval

Let f(x)=x2025−x2000f(x) = x^{2025} - x^{2000}, x∈[0,1]x \in [0, 1] and the minimum value of the function f(x)f(x) in the interval [0,1][0, 1] be (80)80(n)−81(80)^{80}(n)^{-81}. Then nn is equal to
  1. (1)−81-81
  2. (2)−40-40
  3. (3)−41-41
  4. (4)−80-80

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