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Applications of Derivatives

9 JEE Main questions · Maths

  1. MathsJEE Main 21 Jan 2026, Shift 2·Q2·MCQ·Moderate
    Open

    Monotonicity of composite functions

    Let f:R→Rf : \mathbb{R} \to \mathbb{R} be a twice differentiable function such that f′′(x)>0f''(x) > 0 for all x∈Rx \in \mathbb{R} and f′(a−1)=0f'(a-1) = 0, where aa is real number. Let g(x)=f(tan⁡2x−2tan⁡x+a)g(x) = f(\tan^2 x - 2\tan x + a), 0<x<π20 < x < \dfrac{\pi}{2}.

    Consider the following two statements:

    (I) gg is increasing in (0,π4)\left(0, \dfrac{\pi}{4}\right)

    (II) gg is decreasing in (π4,π2)\left(\dfrac{\pi}{4}, \dfrac{\pi}{2}\right)

    Then,

    1. (1)Neither (I) nor (II) is True
    2. (2)Only (II) is True
    3. (3)Only (I) is True
    4. (4)Both (I) and (II) are True
  2. MathsJEE Main 22 Jan 2026, Shift 1·Q5·MCQ·Easy–moderate
    Open

    Absolute minimum on an interval

    Let f(x)=x2025−x2000f(x) = x^{2025} - x^{2000}, x∈[0,1]x \in [0, 1] and the minimum value of the function f(x)f(x) in the interval [0,1][0, 1] be (80)80(n)−81(80)^{80}(n)^{-81}. Then nn is equal to
    1. (1)−81-81
    2. (2)−40-40
    3. (3)−41-41
    4. (4)−80-80
  3. MathsJEE Main 24 Jan 2026, Shift 1·Q24·Numerical·Moderate
    Open

    Monotonicity and local maxima

    Let (2α,α)(2\alpha, \alpha) be the largest interval in which the function f(t)=∣t+1∣t2f(t) = \dfrac{\lvert t + 1\rvert}{t^2}, t<0t < 0, is strictly decreasing. Then the local maximum value of the function g(x)=2log⁡e(x−2)+αx2+4x−αg(x) = 2\log_e(x - 2) + \alpha x^2 + 4x - \alpha, x>2x > 2, is .
  4. MathsJEE Main 24 Jan 2026, Shift 2·Q15·MCQ·Moderate
    Open

    Monotonicity of functions

    Consider the following three statements for the function f:(0,∞)→Rf : (0, \infty) \to \mathbb{R} defined by f(x)=∣log⁡ex∣−∣x−1∣f(x) = \lvert\log_e x\rvert - \lvert x - 1\rvert:
    (I) ff is differentiable at all x>0x > 0.
    (II) ff is increasing in (0,1)(0, 1).
    (III) ff is decreasing in (1,∞)(1, \infty).
    Then.
    1. (1)All (I), (II) and (III) are TRUE.
    2. (2)Only (I) is TRUE.
    3. (3)Only (II) and (III) are TRUE.
    4. (4)Only (I) and (III) are TRUE.
  5. MathsJEE Main 28 Jan 2026, Shift 2·Q23·Numerical·Tough
    Open

    Local maxima and minima

    Let ff be a differentiable function satisfying f(x)=1−2x+∫0xe(x−t)f(t) dt, x∈Rf(x) = 1 - 2x + \int_0^x e^{(x-t)}f(t)\,dt,\ x \in \mathbb{R} and let g(x)=∫0x(f(t)+2)15(t−4)6(t+12)17 dt, x∈R.g(x) = \int_0^x (f(t) + 2)^{15}(t - 4)^6(t + 12)^{17}\,dt,\ x \in \mathbb{R}. If pp and qq are respectively the points of local minima and local maxima of gg, then the value of ∣p+q∣\lvert p + q\rvert is equal to .
  6. MathsJEE Main 2 Apr 2026, Shift 1·Q18·MCQ·Tough
    Open

    Critical points of a function

    The number of critical points of the function f(x)={∣sin⁡xx∣,x≠01,x=0f(x) = \begin{cases} \left\lvert\dfrac{\sin x}{x}\right\rvert, & x \neq 0\\[6pt] 1, & x = 0\end{cases} in the interval (−2π,2π)(-2\pi, 2\pi) is equal to:
    1. (1)1
    2. (2)3
    3. (3)5
    4. (4)7
  7. MathsJEE Main 2 Apr 2026, Shift 2·Q18·MCQ·Moderate
    Open

    Polynomial with given extrema

    Let f(x)f(x) be a polynomial of degree 5, and have extrema at x=1x = 1 and x=−1x = -1. If lim⁡x→0(f(x)x3)=−5\displaystyle\lim_{x\to0}\left(\frac{f(x)}{x^3}\right) = -5, then f(2)−f(−2)f(2) - f(-2) is equal to:
    1. (1)0
    2. (2)50
    3. (3)92
    4. (4)112
  8. MathsJEE Main 4 Apr 2026, Shift 2·Q12·MCQ·Moderate
    Open

    Maxima and minima

    max⁡0≤x≤π(16sin⁡(x2)cos⁡3(x2))\displaystyle\max_{0 \le x \le \pi}\left(16\sin\left(\frac{x}{2}\right)\cos^3\left(\frac{x}{2}\right)\right) is equal to:
    1. (1)332\dfrac{3\sqrt3}{2}
    2. (2)333\sqrt3
    3. (3)434\sqrt3
    4. (4)636\sqrt3
  9. MathsJEE Main 6 Apr 2026, Shift 2·Q17·MCQ·Moderate
    Open

    Maximum and minimum on interval

    Let A=[13−121α01−1]A = \begin{bmatrix} 1 & 3 & -1\\ 2 & 1 & \alpha\\ 0 & 1 & -1\end{bmatrix} be a singular matrix. Let f(x)=∫0x(t2+2t+3)dtf(x) = \displaystyle\int_0^x \left(t^2 + 2t + 3\right)dt, x∈[1,α]x \in [1, \alpha]. If MM and mm are respectively the maximum and the minimum values of ff in [1,α][1, \alpha] then 3(M−m)3(M - m) is equal to:
    1. (1)64
    2. (2)68
    3. (3)72
    4. (4)76
    We corrected a printing error in the original paper

    Source printed the matrix AA between determinant bars (“A=∣…∣A = \lvert\ldots\rvert be a singular matrix”).