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PhysicsJEE Main 22 Jan 2026, Shift 1·Q24·Numerical·Easy–moderate

Rotational Motion · Moment of inertia

A circular disc has radius R1R_1 and thickness T1T_1. Another circular disc made of the same material has radius R2R_2 and thickness T2T_2. If the moments of inertia of both discs are same and R1R2=2\dfrac{R_1}{R_2} = 2 then T1T2=1α\dfrac{T_1}{T_2} = \dfrac{1}{\alpha}. The value of α\alpha is .
We corrected a printing error in the original paper

Source printed “the moment of inertia of both discs are same”.

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