PhysicsJEE Main 21 Jan 2026, Shift 1·Q23·Numerical·Easy–moderate

Rotational Motion · Moment of inertia

Two identical thin rods of mass

M

kg and length

L

m are connected as shown in figure. Moment of inertia of the combined rod system about an axis passing through point P and perpendicular to the plane of the rods is

\dfrac{x}{12}ML^2\ \mathrm{kg\,m^2}

. The value of

x

is .

We corrected a printing error in the original paper

Source printed “ $\dfrac{x}{2}ML^2$ ” (which gives $x = 17/6$ ); corrected to the intended “ $\dfrac{x}{12}ML^2$ ” ( $I = 17ML^2/12$ , source key 17).

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Rotational Motion · Moment of inertia

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