AktiraAktira JEE
ChemistryJEE Main 23 Jan 2026, Shift 1·Q22·Numerical·Moderate

Equilibrium · Degree of dissociation from kp

For the following gas phase equilibrium reaction at constant temperature,

NHX3(g)⇌12 NX2(g)+32 HX2(g)\ce{NH3(g) <=> 1/2 N2(g) + 3/2 H2(g)}

If the total pressure is 3\sqrt{3} atm and the pressure equilibrium constant (KPK_\mathrm{P}) is 9 atm, then the degree of dissociation is given as (x×10−2)−1/2(x\times10^{-2})^{-1/2}.

The value of x is (Nearest integer)

Video solution coming soon

We're animating every PYQ step by step. Subscribe to get them first.

Subscribe

See the full 23 Jan 2026, Shift 1 paper