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JEE Main 2026

JEE Main 23 Jan 2026, Shift 1

75 questions. Answers are hidden — tap “Show answer” under each one.

Physics

  1. Q1 · MCQ · Ray OpticsOpen
    A thin prism with angle 5∘5^\circ of refractive index 1.72 is combined with another prism of refractive index 1.9 to produce dispersion without deviation. The angle of second prism is .
    1. (1)4.5∘4.5^\circ
    2. (2)6∘6^\circ
    3. (3)4∘4^\circ
    4. (4)5∘5^\circ
  2. A small bob A of mass mm is attached to a massless rigid rod of length 1m pivoted at point P and kept at an angle of 60∘60^\circ with vertical as shown in figure. At distance of 1m below point P, an identical bob B is kept at rest on a smooth horizontal surface that extends to a circular track of radius R as shown in figure. If bob B just manages to complete the circular path of radius R upto a point Q after being hit elastically by bob A, then radius R is m.
    1. (1)35\dfrac35
    2. (2)15\dfrac15
    3. (3)2+35\dfrac{2+\sqrt3}{5}
    4. (4)2−35\dfrac{2-\sqrt3}{5}
    We corrected a printing error in the original paper

    Source printed “A small both A”.

  3. Match List-I with List-II.
    List-I (Relation)List-II (Law)
    A.∮E⃗⋅dl⃗=−ddt∮B⃗⋅da⃗\displaystyle\oint\vec E\cdot d\vec l = -\frac{d}{dt}\oint\vec B\cdot d\vec aI.Ampere's circuital law.
    B.∮B⃗⋅dl⃗=μ0(I+ϵ0dϕEdt)\displaystyle\oint\vec B\cdot d\vec l = \mu_0\left(I + \epsilon_0\frac{d\phi_E}{dt}\right)II.Faraday's laws of electromagnetic induction.
    (C)∮E⃗⋅da⃗=1ϵ0∫ρ dv\displaystyle\oint\vec E\cdot d\vec a = \frac{1}{\epsilon_0}\int\rho\,dvIII.Ampere-Maxwell law
    (D)∮B⃗⋅dl⃗=μ0I\displaystyle\oint\vec B\cdot d\vec l = \mu_0 IIV.Gauss's law of electrostatics
    Choose the correct answer from the options given below:
    1. (1)A-II, B-III, C-I, D-IV
    2. (2)A-II, B-III, C-IV, D-I
    3. (3)A-I, B-IV, C-III, D-II
    4. (4)A-IV, B-I, C-II, D-III
    We corrected a printing error in the original paper

    Source printed row B as “∮B⋅dl⃗=μ0(1+ϵ0dϕEdt)\oint B\cdot d\vec l = \mu_0\left(1 + \epsilon_0\frac{d\phi_E}{dt}\right)” (digit 1 for the current II, no arrow on BB).

  4. Four persons measure the length of a rod as 20.00 cm, 19.75 cm, 17.01 cm and 18.25 cm. The relative error in the measurement of average length of the rod is:
    1. (1)0.24
    2. (2)0.18
    3. (3)0.06
    4. (4)0.08
  5. The de Broglie wavelength of an oxygen molecule at 27∘27^\circC is x×10−12x\times10^{-12} m. The value of xx is (take Planck's constant =6.63×10−34= 6.63\times10^{-34} J.s, Boltzmann constant =1.38×10−23= 1.38\times10^{-23} J/K, mass of oxygen molecule =5.31×10−26= 5.31\times10^{-26} kg).
    1. (1)26
    2. (2)24
    3. (3)30
    4. (4)20
    We corrected a printing error in the original paper

    Source printed “mass of oxygen. Molecule”.

  6. Q6 · MCQ · OscillationsOpen
    A simple pendulum of string length 30 cm performs 20 oscillations in 10s. The length of the string required for the pendulum to perform 40 oscillations in the same time duration is cm. [Assume that the mass of the pendulum remains same.]
    1. (1)120
    2. (2)0.75
    3. (3)7.5
    4. (4)15
  7. Two blocks with masses 100g and 200g are attached to the ends of springs A and B as shown in figure. The energy stored in A is E. The energy stored in B, when spring constants kAk_A, kBk_B of A and B, respectively satisfy the relation 4kA=3kB4k_A = 3k_B, is:
    1. (1)4E
    2. (2)2E
    3. (3)3E
    4. (4)43\dfrac43E
  8. The moment of inertia of a square loop made of four uniform solid cylinders, each having radius R and length L (R<L)(R < L) about an axis passing through the mid points of opposite sides, is (Take the mass of the entire loop as M):
    1. (1)38MR2+712ML2\dfrac38 MR^2 + \dfrac{7}{12}ML^2
    2. (2)34MR2+16ML2\dfrac34 MR^2 + \dfrac16 ML^2
    3. (3)34MR2+712ML2\dfrac34 MR^2 + \dfrac{7}{12}ML^2
    4. (4)38MR2+16ML2\dfrac38 MR^2 + \dfrac16 ML^2
  9. A wire of uniform resistance λ Ω\lambda\ \Omega/m is bent into a circle of radius r and another piece of wire with length 2r is connected between points A and B (AOB) as shown in figure. The equivalent resistance between points A and B is Ω\Omega.
    1. (1)3πλr8\dfrac{3\pi\lambda r}{8}
    2. (2)(π+1) 2rλ(\pi + 1)\,2r\lambda
    3. (3)6πλr3π+16\dfrac{6\pi\lambda r}{3\pi + 16}
    4. (4)2πλr2\pi\lambda r
  10. The strain-stress plot for materials A,B,C and D is shown in the figure. Which material has the largest Young's modulus?
    1. (1)C
    2. (2)D
    3. (3)A
    4. (4)B
  11. Q11 · MCQ · Ray OpticsOpen
    Consider light travelling from a medium A to medium B separated by a plane interface. If the light undergoes total internal reflection during its travel from medium A to B and the speed of light in media A and B are 2.4×1082.4\times10^{8} m/s and 2.7×1082.7\times10^{8} m/s respectively, then the value of critical angle is:
    1. (1)cot⁡−1(313)\cot^{-1}\left(\dfrac{3}{\sqrt{13}}\right)
    2. (2)sin⁡−1(98)\sin^{-1}\left(\dfrac98\right)
    3. (3)tan⁡−1(817)\tan^{-1}\left(\dfrac{8}{\sqrt{17}}\right)
    4. (4)cos⁡−1(89)\cos^{-1}\left(\dfrac89\right)
  12. The following diagram shows a Zener diode as a voltage regulator. The Zener diode is rated at VZ=5V_Z = 5V and the desired current in load is 5 mA. The unregulated voltage source can supply upto 25V. Considering the Zener diode can withstand four times of the load current, the value of resistor RSR_S (shown in circuit) should be Ω\Omega.
    1. (1)4000
    2. (2)10
    3. (3)100
    4. (4)1000

    Flawed question. Dropped in the source; as printed RS=(25−5) V/(20+5) mA=800 ΩR_S = (25-5)\,\mathrm{V}/(20+5)\,\mathrm{mA} = 800\ \Omega, not among the options, and no evident intended version. It is shown for completeness and is left out of practice tests.

  13. Q13 · MCQ · AtomsOpen
    In hydrogen atom spectrum, (R→R \rightarrow Rydberg's constant)
    A.the maximum wavelength of the radiation of Lyman series is 43R\dfrac{4}{3R}
    B.the Balmer series lies in the visible region of the spectrum
    C.the minimum wavelength of the radiation of Paschen series is 9R\dfrac{9}{R}
    D.the minimum wavelength of Lyman series is 54R\dfrac{5}{4R}
    Choose the correct answer from the options given below:
    1. (1)B, D Only
    2. (2)A, B and C Only
    3. (3)A, B and D Only
    4. (4)A, B Only
  14. An object is projected with kinetic energy K from a point A at an angle 60∘60^\circ with the horizontal. The ratio of the difference in kinetic energies at points B and C to that at point A (see figure), in the absence of air friction is:
    1. (1)1 : 2
    2. (2)2 : 3
    3. (3)1 : 4
    4. (4)3 : 4
    We corrected a printing error in the original paper

    Source printed “the difference in kinetic energies points B and C” (“at” missing).

  15. Two point charges 2q and q are placed at vertex A and centre of face CDEF of the cube as shown in figure. The electric flux passing through the cube is:
    1. (1)3qε0\dfrac{3q}{\varepsilon_0}
    2. (2)qε0\dfrac{q}{\varepsilon_0}
    3. (3)3q2ε0\dfrac{3q}{2\varepsilon_0}
    4. (4)3q4ε0\dfrac{3q}{4\varepsilon_0}
  16. A 20 m long uniform copper wire held horizontally is allowed to fall under the gravity (g=10 m/s2g = 10\ \mathrm{m/s^2}) through a uniform horizontal magnetic field of 0.5 Gauss perpendicular to the length of the wire. The induced EMF across the wire when it travels a vertical distance of 200 m is mV.
    1. (1)0.2100.2\sqrt{10}
    2. (2)201020\sqrt{10}
    3. (3)2102\sqrt{10}
    4. (4)20010200\sqrt{10}
    We corrected a printing error in the original paper

    Source printed “across the wire it travells”.

  17. Two small balls with masses m and 2m are attached to both ends of a rigid rod of length d and negligible mass. If angular momentum of this system is L about an axis (A) passing through its centre of mass and perpendicular to the rod then angular velocity of the system about A is:
    1. (1)32Lmd2\dfrac32\dfrac{L}{md^2}
    2. (2)2Lmd2\dfrac{2L}{md^2}
    3. (3)43Lmd2\dfrac43\dfrac{L}{md^2}
    4. (4)2L5md2\dfrac{2L}{5md^2}
  18. In a perfectly inelastic collision, two spheres made of the same material with masses 15 kg and 25 kg, moving in opposite directions with speeds of 10 m/s and 30 m/s, respectively, strike each other and stick together. The rise in temperature (in ∘^\circC), if all the heat produced during the collision is retained by these spheres, is:

    (specific heat of sphere material 31 cal/kg. ∘^\circC and 1 cal =4.2= 4.2 J)

    1. (1)1.75
    2. (2)1.44
    3. (3)1.15
    4. (4)1.95
  19. In a screw gauge, the zero of the circular scale lies 3 divisions above the horizontal pitch line when their metallic studs are brought in contact. Using this instrument thickness of a sheet is measured. If pitch scale reading is 1 mm and the circular scale reading is 51 then the correct thickness of the sheet is mm.

    [Assume least count is 0.01 mm]

    1. (1)1.50
    2. (2)1.48
    3. (3)1.54
    4. (4)1.51
  20. Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).

    Consider a ferromagnetic material:

    Assertion (A): The individual atoms in a ferromagnetic material possess a magnetic dipole moment and interact with one another in such a way that they spontaneously align themselves forming domains.

    Reason (R): At high enough temperature, the domain structure of ferromagnetic material disintegrates. Thus, magnetization will disappear at high enough temperature known as Curie temperature.

    In the light of the above statements, choose the correct answer from the options given below:

    1. (1)(A) is true but (R) is false
    2. (2)Both (A) and (R) are true but (R) is not the correct explanation of (A)
    3. (3)Both (A) and (R) are true and (R) is the correct explanation of (A)
    4. (4)(A) is false but (R) is true
  21. Q21 · Numerical · Electromagnetic InductionOpen
    A simple pendulum made of mass 10 g and a metallic wire of length 10 cm is suspended vertically in a uniform magnetic field of 2 T. The magnetic field direction is perpendicular to the plane of oscillations of the pendulum. If the pendulum is released from an angle of 60∘60^\circ with vertical, then maximum induced EMF between the point of suspension and point of oscillation is mV. (Take g=10 m/s2g = 10\ \mathrm{m/s^2})
  22. Q22 · Numerical · Electromagnetic WavesOpen

    The equation of the electric field of an electromagnetic wave propagating through free space is given by: E=377 sin⁡(6.27×103t−2.09×10−5x) N/CE = \sqrt{377}\,\sin(6.27\times10^{3}t - 2.09\times10^{-5}x)\ \mathrm{N/C} The average power of the electromagnetic wave is (1α)W/m2\left(\dfrac{1}{\alpha}\right)\mathrm{W/m^2}. The value of α\alpha is

    (Take μ0ε0=377 in SI units)\left(\text{Take } \sqrt{\dfrac{\mu_0}{\varepsilon_0}} = 377 \text{ in SI units}\right)

    We corrected a printing error in the original paper

    Source printed “he average power”.

  23. Q23 · Numerical · Alternating CurrentOpen
    Using a variable-frequency a.c. voltage source, the maximum current measured in the given LCR circuit is 50 mA for V=5sin⁡(100t)V = 5\sin(100t). The values of L and R are shown in the figure. The capacitance of the capacitor (C) used is μ\muF.
  24. Q24 · Numerical · Wave OpticsOpen
    In two separate Young's double-slit experimental set-ups, two monochromatic light sources of different wavelengths are used to get fringes of equal width. The ratios of the slit separations and that of the wavelengths of light used are 2 : 1 and 1 : 2 respectively. The corresponding ratio of the distances between the slits and the respective screens (D1/D2)(D_1/D_2) is .
  25. The space between the plates of a parallel-plate capacitor of capacitance C (without any dielectric) is now filled with three dielectric slabs of dielectric constants K1=2K_1 = 2, K2=3K_2 = 3, and K3=5K_3 = 5 (as shown in the figure). If new capacitance is n3C\dfrac{n}{3}C then the value of n is .

Chemistry

  1. Which of the following statements regarding the energy of the stationary state is true in the following one-electron system ?
    1. (1)−1.09×10−18-1.09\times10^{-18} J for second orbit of H atom.
    2. (2)+2.18×10−18+2.18\times10^{-18} J for second orbit of HeX+\ce{He+} ion
    3. (3)+8.72×10−18+8.72\times10^{-18} J for first orbit of HeX+\ce{He+} ion
    4. (4)−2.18×10−18-2.18\times10^{-18} J for third orbit of LiX2+\ce{Li^{2+}} ion
  2. Q2 · MCQ · SolutionsOpen
    Which one of the following graphs accurately represents the plot of partial pressure of CSX2\ce{CS2} vs its mole fraction in a mixture of acetone and CSX2\ce{CS2} at constant temperature ?
    1. (1)
    2. (2)
    3. (3)
    4. (4)
  3. The correct trend in the first ionization enthalpies of the elements in the 3rd^\text{rd} period of periodic table is:
    1. (1)Al << Si << S << P << Cl
    2. (2)Al << S << P << Si << Cl
    3. (3)Si << S << Al << P << Cl
    4. (4)S << Si << Al << P << Cl
  4. The correct sequence of reagents for the above conversion of X to Y is :
    1. (1)(i) NaOH (aq) (ii) Jones reagent (iii) HX3OX+\ce{H3O+}
    2. (2)(i) BX2HX6\ce{B2H6}/HX2OX2\ce{H2O2} (ii) NaOEt (iii) Jones reagent
    3. (3)(i) Jones reagent (ii) NaOEt (iii) Hot KMnOX4\ce{KMnO4}/KOH
    4. (4)(i) NaOEt (ii) BX2HX6\ce{B2H6}/HX2OX2\ce{H2O2} (iii) Jones reagent
    We corrected a printing error in the original paper

    Option (2): source printed “BX2HX6\ce{B2H6}/HX2OX2\ce{H2O2} (ii) NaOEt (iii) Jones reagent” without the step label “(i)”.

  5. In the given electrochemical cell, Ag(s)∣|AgCl(s)∣|FeClX2\ce{FeCl2}(aq), FeClX3\ce{FeCl3}(aq)∣|Pt(s) at 298 K, the cell potential (EcellE_\mathrm{cell}) will increase when :
    • (A)Concentration of FeX2+\ce{Fe^{2+}} is increased.
    • (B)Concentration of FeX3+\ce{Fe^{3+}} is decreased
    • (C)Concentration of FeX2+\ce{Fe^{2+}} is decreased
    • (D)Concentration of FeX3+\ce{Fe^{3+}} is increased
    • (E)Concentration of ClX−\ce{Cl-} is increased
    Choose the correct answer from the options given below :
    1. (1)A and B only
    2. (2)A and E only
    3. (3)B only
    4. (4)C, D and E only
    We corrected a printing error in the original paper

    Source labelled the fifth statement “(D)” (two statements (D), none (E), while the options refer to E).

  6. ‘x' is the product which is obtained from propanenitrile and stannous chloride in the presence of hydrochloric acid followed by hydrolysis. ‘y' is the product which is obtained from the but-2-ene by the ozonolysis followed by hydrolysis. From the following, which product is not obtained when one mole of ‘x' and one mole of ‘y' react with each other in the presence of alkali followed by heating ?
    1. (1)2-Methylbut-2-enal
    2. (2)Pent-2-enal
    3. (3)2-Methylpent-2-enal
    4. (4)3-Methylbut-2-enal
  7. Q7 · MCQ · AminesOpen
    Consider the following sequence of reactions.
    4-Nitrotoluene

    Assuming that the reaction proceeds to completion, then 137 mg of 4-nitrotoluene will produce mg of B.

    (Given molar mass in g mol−1^{-1} H : 1, C : 12, N : 14, O : 16, Br : 80)

    1. (1)301
    2. (2)146
    3. (3)228
    4. (4)208
  8. Q8 · MCQ · ThermodynamicsOpen
    A cup of water at 5∘^\circC (system) is placed in a microwave oven and the oven is turned on for one minute during which, the water begins to boil. Which of the following option is true ?
    1. (1)q=+q = +ve, w=0w = 0, ΔU=−\Delta U = -ve
    2. (2)q=+q = +ve, w=−w = -ve, ΔU=+\Delta U = +ve
    3. (3)q=−q = -ve, w=−w = -ve, ΔU=−\Delta U = -ve
    4. (4)q=+q = +ve, w=−w = -ve, ΔU=−\Delta U = -ve
  9. Given below are two statements :

    Statement I : [CoBrX4]X2−\ce{[CoBr4]^{2-}} ion will absorb light of lower energy than [CoClX4]X2−\ce{[CoCl4]^{2-}} ion.

    Statement II : In [CoIX4]X2−\ce{[CoI4]^{2-}} ion, the energy separation between the two set of d-orbitals is more than [CoClX4]X2−\ce{[CoCl4]^{2-}} ion.

    In the light of the above statements, choose the correct answer from the options given below :

    1. (1)Both Statement I and Statement II are false
    2. (2)Statement I is true but Statement II is false
    3. (3)Statement I is false but Statement II is true
    4. (4)Both Statement I and Statement II are true
  10. Q10 · MCQ · HydrocarbonsOpen
    But-2-yne and hydrogen (one mole each) are separately treated with (i) Pd/C and (ii) Na/liq. NHX3\ce{NH3} to give the products X and Y respectively.
    Identify the incorrect statements.
    • (A)X and Y are stereoisomers.
    • (B)Dipole moment of X is zero
    • (C)Boiling point of X is higher than Y.
    • (D)X and Y react with OX3\ce{O3}/Zn + HX2O\ce{H2O} to give different products.
    Choose the correct answer from the options given below :
    1. (1)B and C only
    2. (2)B and D only
    3. (3)A and B only
    4. (4)A and C only
  11. Given,

    (A) n=5n = 5, ml=−1m_l = -1

    (B) n=3n = 3, l=2l = 2, ml=−1m_l = -1, ms=+12m_s = +\dfrac{1}{2}

    The maximum number of electron(s) in an atom that can have the quantum numbers as given in (A) and (B) respectively are :

    1. (1)26 and 1
    2. (2)4 and 1
    3. (3)2 and 4
    4. (4)8 and 1
    We corrected a printing error in the original paper

    Source printed the magnetic quantum number as “m1_1” and the azimuthal quantum number in (B) as “1 = 2” (digit 1 for l).

  12. Q12 · MCQ · HydrocarbonsOpen
    Consider the following compounds
    Arrange these compounds in the increasing order of reactivity with nitrating mixture.
    1. (1)c << a << b
    2. (2)b << c << a
    3. (3)c << b << a
    4. (4)b << a << c
  13. The statements that are incorrect about the nickel (II) complex of dimethylglyoxime are :
    • (A)It is red in colour
    • (B)It has a high solubility in water at pH = 9
    • (C)The Ni ion has two unpaired d-electrons
    • (D)The N – Ni – N bond angle is almost close to 90∘^\circ
    • (E)The complex contains four five-membered metallacycles (metal containing rings)
    Choose the correct answer from the options given below :
    1. (1)C and E only
    2. (2)A, D and B only
    3. (3)B, C and E only
    4. (4)C and D only
  14. Q14 · MCQ · BiomoleculesOpen
    From the given following (A to D) cyclic structures, those which will not react with Tollen's reagent are :
    1. (1)B and D
    2. (2)A and D
    3. (3)A and B
    4. (4)B and C
  15. Q15 · MCQ · Chemical BondingOpen
    Identify the molecule(X) with maximum number of lone pairs of electrons (obtained using Lewis dot structure) among HNOX3\ce{HNO3}, HX2SOX4\ce{H2SO4}, NFX3\ce{NF3} and OX3\ce{O3}. Choose the correct bond angle made by the central atom of the molecule (X).
    1. (1)120∘^\circ
    2. (2)107∘^\circ
    3. (3)102∘^\circ
    4. (4)116∘^\circ
  16. Match List-I with List-II.
    List-IList-II
    Functional group (detection)Change observed during detection
    (A)Unsaturation (Baeyer's test)(I)Red colour Appears
    (B)Alcoholic group (Ceric ammonium nitrate test)(II)Silver mirror appears
    (C)Aldehyde group (Tollen's reagent)(III)Violet colour appears
    (D)Phenolic group (FeClX3\ce{FeCl3} test)(IV)Discharge of pink colour
    Choose the correct answer from the options given below :
    1. (1)A-III, B-IV, C-II, D-I
    2. (2)A-III, B-IV, C-I, D-II
    3. (3)A-IV, B-I, C-II, D-III
    4. (4)A-IV, B-III, C-II, D-I
  17. Given below are two statements :

    Statement-I : Sublimation is used for the separation and purification of compounds with low melting point.

    Statement-II : The boiling point of a liquid increases as the external pressure is reduced.

    In the light of the above statements, choose the correct answer from the options given below :

    1. (1)Statement-I is false but Statement-II is true.
    2. (2)Statement-I is true but Statement-II is false.
    3. (3)Both Statement-I and Statement-II are true.
    4. (4)Both Statement-I and Statement-II are false.
  18. Q18 · MCQ · AminesOpen
    Compound ‘P' undergoes the following sequence of reactions :
    ‘P' is :
    1. (1)
    2. (2)
    3. (3)
    4. (4)
  19. The correct statements from the following are :
    • (A)Ionic radii of trivalent cations of group 13 elements decrease down the group.
    • (B)Electronegativity of group 13 elements decreases down the group.
    • (C)Among the group 13 elements, Boron has highest first ionisation enthalpy.
    • (D)The trichloride and triiodide of group 13 elements are covalent in nature.
    Choose the correct answer from the options given below :
    1. (1)A and C only
    2. (2)A and D only
    3. (3)C and D only
    4. (4)B and D only
    We corrected a printing error in the original paper

    Source printed “Ionic radii … decreases down the group” and “from the otpions given below”.

  20. Q20 · MCQ · EquilibriumOpen

    Consider the general reaction given below at 400 K

    x A(g)⇌y B(g)\ce{xA(g) <=> yB(g)}

    The values of KpK_\mathrm{p} and KcK_\mathrm{c} are studied under the same condition of temperature but variation in x and y.

    (i) Kp=85.87K_\mathrm{p} = 85.87 and Kc=2.586K_\mathrm{c} = 2.586 appropriate units

    (ii) Kp=0.862K_\mathrm{p} = 0.862 and Kc=28.62K_\mathrm{c} = 28.62 appropriate units

    The value of x and y in (i) and (ii) respectively are:

    1. (1)(i) 3, 1 ; (ii) 3, 1
    2. (2)(i) 4, 1 ; (ii) 4, 1
    3. (3)(i) 1, 3 ; (ii) 2, 1
    4. (4)(i) 1, 2 ; (ii) 2, 1
  21. Q21 · Numerical · Chemical KineticsOpen
    For the thermal decomposition of reaction AB(g), the following is constructed.

    The half life of the reaction is ‘x' min.

    x = min. (Nearest integer)

  22. Q22 · Numerical · EquilibriumOpen

    For the following gas phase equilibrium reaction at constant temperature,

    NHX3(g)⇌12 NX2(g)+32 HX2(g)\ce{NH3(g) <=> 1/2 N2(g) + 3/2 H2(g)}

    If the total pressure is 3\sqrt{3} atm and the pressure equilibrium constant (KPK_\mathrm{P}) is 9 atm, then the degree of dissociation is given as (x×10−2)−1/2(x\times10^{-2})^{-1/2}.

    The value of x is (Nearest integer)

  23. Q23 · Numerical · Some Basic ConceptsOpen

    x mg of pure HCl was used to make an aqueous solution. 25.0 mL of 0.1 M Ba(OH)X2\ce{Ba(OH)2} solution is used when the HCl solution was titrated against it. The numerical value of x is × 10−1\times\,10^{-1}. (Nearest integer)

    Given : Molar mass of HCl and Ba(OH)X2\ce{Ba(OH)2} are 36.5 and 171.0 g mol−1^{-1} respectively.

  24. Q24 · Numerical · Haloalkanes & HaloarenesOpen
    Consider all the structural isomers with molecular formula CX5HX11Br\ce{C5H11Br} that are separately treated with KOH (aq) to give respective substitution products, without any rearrangement. The number of products which can exhibit optical isomerism from these is .
    We corrected a printing error in the original paper

    Source printed “Consider all the structural isomers with molecular formula CX5HX11Br\ce{C5H11Br} are separately treated” (“that” missing).

  25. Q25 · Numerical · Coordination CompoundsOpen
    The crystal field stabilisation energy of [Co(oxalate)X3]X3−\ce{[Co(oxalate)3]^{3-}} complex is ‘n' times that of the [Cr(oxalate)X3]X3−\ce{[Cr(oxalate)3]^{3-}} complex. Here ‘n' is . [Assume Δo≫P\Delta_\mathrm{o} \gg P]
    We corrected a printing error in the original paper

    Source printed “The crystal field splitting energy”; corrected to the intended “crystal field stabilisation energy” (the splitting Δo\Delta_\mathrm{o} is about the same for both oxalato complexes; the key 2 is the CFSE ratio −2.4Δo/−1.2Δo-2.4\Delta_\mathrm{o}/-1.2\Delta_\mathrm{o}).

Maths

  1. Let the domain of the function f(x)=log⁡3log⁡5log⁡7(9x−x2−13)f(x) = \log_3\log_5\log_7(9x - x^2 - 13) be the interval (m,n)(m, n). Let the hyperbola x2a2−y2b2=1\dfrac{x^2}{a^2} - \dfrac{y^2}{b^2} = 1 have eccentricity n3\dfrac{n}{3} and the length of the latus rectum 8m3\dfrac{8m}{3}. Then b2−a2b^2 - a^2 is equal to:
    1. (1)5
    2. (2)11
    3. (3)9
    4. (4)7
  2. Let f(x)=∫(2−x2)⋅ex(1+x)(1−x)3/2 dxf(x) = \displaystyle\int\frac{(2 - x^2)\cdot e^x}{\left(\sqrt{1+x}\right)(1-x)^{3/2}}\,dx. If f(0)=0f(0) = 0, then f(12)f\left(\dfrac12\right) is equal to:
    1. (1)3e−1\sqrt{3e} - 1
    2. (2)2e+1\sqrt{2e} + 1
    3. (3)2e−1\sqrt{2e} - 1
    4. (4)3e+1\sqrt{3e} + 1
    We corrected a printing error in the original paper

    Source printed “If f(0)−0f(0) - 0” (minus sign instead of the equals sign).

  3. Q3 · MCQ · VectorsOpen
    Let a⃗=−i^+j^+2k^\vec a = -\hat i + \hat j + 2\hat k, b⃗=i^−j^−3k^\vec b = \hat i - \hat j - 3\hat k, c⃗=a⃗×b⃗\vec c = \vec a\times\vec b and d⃗=c⃗×a⃗\vec d = \vec c\times\vec a. Then (a⃗−b⃗)⋅d⃗\left(\vec a - \vec b\right)\cdot\vec d is equal to:
    1. (1)4
    2. (2)−4-4
    3. (3)−2-2
    4. (4)2
  4. Q4 · MCQ · Straight LinesOpen
    A rectangle is formed by the lines x=0x = 0, y=0y = 0, x=3x = 3 and y=4y = 4. Let the line LL be perpendicular to 3x+y+6=03x + y + 6 = 0 and divide the area of the rectangle into two equal parts. Then the distance of the point (12,−5)\left(\dfrac12, -5\right) from the line LL is equal to:
    1. (1)252\sqrt5
    2. (2)3103\sqrt{10}
    3. (3)10\sqrt{10}
    4. (4)2102\sqrt{10}
  5. Q5 · MCQ · Conic SectionsOpen
    Let the line y−x=1y - x = 1 intersect the ellipse x22+y21=1\dfrac{x^2}{2} + \dfrac{y^2}{1} = 1 at the points AA and BB. Then the angle made by the line segment ABAB at the center of the ellipse is:
    1. (1)π−tan⁡−1(14)\pi - \tan^{-1}\left(\dfrac14\right)
    2. (2)π2+tan⁡−1(14)\dfrac{\pi}{2} + \tan^{-1}\left(\dfrac14\right)
    3. (3)π2+2tan⁡−1(14)\dfrac{\pi}{2} + 2\tan^{-1}\left(\dfrac14\right)
    4. (4)π2−tan⁡−1(14)\dfrac{\pi}{2} - \tan^{-1}\left(\dfrac14\right)
  6. Let A={−2,−1,0,1,2,3,4}A = \{-2, -1, 0, 1, 2, 3, 4\}. Let RR be a relation on AA defined by xRyxRy if and only if 2x+y≤22x + y \le 2. Let ll be the number of elements in RR. Let mm and nn be the minimum number of elements required to be added in RR to make it reflexive and symmetric relations respectively. Then l+m+nl + m + n is equal to:
    1. (1)32
    2. (2)34
    3. (3)33
    4. (4)35
  7. Let y=y(x)y = y(x) be the solution of the differential equation x4 dy+(4x3y+2sin⁡x) dx=0,x>0,y(π2)=0.x^4\,dy + (4x^3y + 2\sin x)\,dx = 0,\quad x > 0,\quad y\left(\frac{\pi}{2}\right) = 0. Then π4y(π3)\pi^4 y\left(\dfrac{\pi}{3}\right) is equal to:
    1. (1)81
    2. (2)92
    3. (3)64
    4. (4)72
  8. If α\alpha and β\beta (α<β)(\alpha < \beta) are the roots of the equation (−2+3)(∣x−3∣)+(x−6x)+(9−23)=0,\left(-2 + \sqrt3\right)\left(\left\lvert\sqrt x - 3\right\rvert\right) + \left(x - 6\sqrt x\right) + \left(9 - 2\sqrt3\right) = 0, x≥0x \ge 0, then βα+αβ\sqrt{\dfrac{\beta}{\alpha}} + \sqrt{\alpha\beta} is equal to:
    1. (1)8
    2. (2)9
    3. (3)10
    4. (4)11
  9. Let f(x)={ax2+2ax+34x2+4x−3,x≠−32,12b,x=−32,12f(x) = \begin{cases} \dfrac{ax^2 + 2ax + 3}{4x^2 + 4x - 3}, & x \neq -\dfrac32, \dfrac12\\[2ex] b, & x = -\dfrac32, \dfrac12\end{cases} be continuous at x=−32x = -\dfrac32. If f∘f(x)=75f\circ f(x) = \dfrac75, then xx is equal to:
    1. (1)2
    2. (2)1
    3. (3)0
    4. (4)1.4
  10. The value of the integral ∫π245π24dx1+tan⁡2x3\displaystyle\int_{\frac{\pi}{24}}^{\frac{5\pi}{24}}\frac{dx}{1 + \sqrt[3]{\tan 2x}} is:
    1. (1)π12\dfrac{\pi}{12}
    2. (2)π18\dfrac{\pi}{18}
    3. (3)π6\dfrac{\pi}{6}
    4. (4)π3\dfrac{\pi}{3}
  11. Among the statements:

    I: If ∣1cos⁡αcos⁡βcos⁡α1cos⁡γcos⁡βcos⁡γ1∣=∣0cos⁡αcos⁡βcos⁡α0cos⁡γcos⁡βcos⁡γ0∣\begin{vmatrix} 1 & \cos\alpha & \cos\beta\\ \cos\alpha & 1 & \cos\gamma\\ \cos\beta & \cos\gamma & 1\end{vmatrix} = \begin{vmatrix} 0 & \cos\alpha & \cos\beta\\ \cos\alpha & 0 & \cos\gamma\\ \cos\beta & \cos\gamma & 0\end{vmatrix}, then cos⁡2α+cos⁡2β+cos⁡2γ=32\cos^2\alpha + \cos^2\beta + \cos^2\gamma = \dfrac32, and

    II: If ∣x2+xx+1x−22x2+3x−13x3x−3x2+2x+32x−12x−1∣=px+q\begin{vmatrix} x^2 + x & x + 1 & x - 2\\ 2x^2 + 3x - 1 & 3x & 3x - 3\\ x^2 + 2x + 3 & 2x - 1 & 2x - 1\end{vmatrix} = px + q, then p2=196q2p^2 = 196q^2,

    1. (1)both are false
    2. (2)only II is true
    3. (3)both are true
    4. (4)only I is true
  12. Q12 · MCQ · Binomial TheoremOpen
    The value of 100C5051+100C5152+…+100C100101\dfrac{{}^{100}C_{50}}{51} + \dfrac{{}^{100}C_{51}}{52} + \ldots + \dfrac{{}^{100}C_{100}}{101} is:
    1. (1)2101100\dfrac{2^{101}}{100}
    2. (2)2100100\dfrac{2^{100}}{100}
    3. (3)2101101\dfrac{2^{101}}{101}
    4. (4)2100101\dfrac{2^{100}}{101}
  13. Q13 · MCQ · StatisticsOpen
    Let the mean and variance of 8 numbers −10-10, −7-7, −1-1, xx, yy, 9, 2, 16 be 72\dfrac72 and 2934\dfrac{293}{4}, respectively. Then the mean of 4 numbers xx, yy, x+y+1x + y + 1, ∣x−y∣\lvert x - y\rvert is:
    1. (1)11
    2. (2)9
    3. (3)10
    4. (4)12
  14. Q14 · MCQ · Binomial TheoremOpen
    The sum of all possible values of n∈Nn \in \mathbb{N}, so that the coefficients of xx, x2x^2 and x3x^3 in the expansion of (1+x2)2(1+x)n(1 + x^2)^2(1 + x)^n, are in arithmetic progression is:
    1. (1)3
    2. (2)7
    3. (3)12
    4. (4)9
  15. Q15 · MCQ · 3D GeometryOpen
    The vertices BB and CC of a triangle ABCABC lie on the line x1=1−y−2=z−23\dfrac{x}{1} = \dfrac{1 - y}{-2} = \dfrac{z - 2}{3}. The coordinates of AA and BB are (1,6,3)(1, 6, 3) and (4,9,α)(4, 9, \alpha) respectively and CC is at a distance of 10 units from BB. The area (in sq. units) of ΔABC\Delta ABC is:
    1. (1)5135\sqrt{13}
    2. (2)151315\sqrt{13}
    3. (3)201320\sqrt{13}
    4. (4)101310\sqrt{13}
  16. Q16 · MCQ · TrigonometryOpen
    Number of solutions of 3cos⁡2θ+8cos⁡θ+33=0\sqrt3\cos2\theta + 8\cos\theta + 3\sqrt3 = 0, θ∈[−3π,2π]\theta \in [-3\pi, 2\pi] is:
    1. (1)0
    2. (2)5
    3. (3)3
    4. (4)4
  17. Q17 · MCQ · Complex NumbersOpen
    Let S={z:3≤∣2z−3(1+i)∣≤7}S = \{z : 3 \le \lvert 2z - 3(1 + i)\rvert \le 7\} be a set of complex numbers. Then min⁡z∈S∣(z+12(5+3i))∣\displaystyle\min_{z\in S}\left\lvert\left(z + \frac12(5 + 3i)\right)\right\rvert is equal to:
    1. (1)12\dfrac12
    2. (2)32\dfrac32
    3. (3)2
    4. (4)52\dfrac52
  18. Q18 · MCQ · TrigonometryOpen
    Let α\alpha and β\beta respectively be the maximum and the minimum values of the function f(θ)=4(sin⁡4(7π2−θ)+sin⁡4(11π+θ))−2(sin⁡6(3π2−θ)+sin⁡6(9π−θ)),θ∈R.f(\theta) = 4\left(\sin^4\left(\frac{7\pi}{2} - \theta\right) + \sin^4(11\pi + \theta)\right) - 2\left(\sin^6\left(\frac{3\pi}{2} - \theta\right) + \sin^6(9\pi - \theta)\right),\quad \theta \in \mathbb{R}. Then α+2β\alpha + 2\beta is equal to:
    1. (1)4
    2. (2)5
    3. (3)3
    4. (4)6
  19. A building construction work can be completed by two masons AA and BB together in 22.5 days. Mason AA alone can complete the construction work in 24 days less than mason BB alone. Then mason AA alone will complete the construction work in:
    1. (1)24 days
    2. (2)42 days
    3. (3)30 days
    4. (4)36 days
  20. Q20 · MCQ · 3D GeometryOpen
    Let the direction cosines of two lines satisfy the equations: 4ℓ+m−n=04\ell + m - n = 0 and 2mn+10nℓ+3ℓm=02mn + 10n\ell + 3\ell m = 0. Then the cosine of the acute angle between these lines is:
    1. (1)1038\dfrac{10}{\sqrt{38}}
    2. (2)20338\dfrac{20}{3\sqrt{38}}
    3. (3)10738\dfrac{10}{7\sqrt{38}}
    4. (4)10338\dfrac{10}{3\sqrt{38}}
  21. Q21 · Numerical · Matrices & DeterminantsOpen
    Let ∣A∣=6\lvert A\rvert = 6, where AA is a 3×33\times3 matrix. If ∣adj⁡(3adj⁡(A2⋅adj⁡(2A)))∣=2m⋅3n\lvert\operatorname{adj}(3\operatorname{adj}(A^2\cdot\operatorname{adj}(2A)))\rvert = 2^m\cdot3^n, m,n∈Nm, n \in \mathbb{N}, then m+nm + n is equal to .
  22. Q22 · Numerical · Area under CurvesOpen
    Let the area of the region bounded by the curve y=max⁡{sin⁡x,cos⁡x}y = \max\{\sin x, \cos x\}, lines x=0x = 0, x=3π2x = \dfrac{3\pi}{2}, and the xx-axis be AA. Then, A+A2A + A^2 is equal to .
  23. Q23 · Numerical · Differential EquationsOpen
    Let ff be a twice differentiable non-negative function such that (f(x))2=25+∫0x((f(t))2+(f′(t))2)dt.(f(x))^2 = 25 + \int_0^x\left((f(t))^2 + (f'(t))^2\right)dt. Then the mean of f(log⁡e(1)),f(log⁡e(2)),…,f(log⁡e(625))f(\log_e(1)), f(\log_e(2)), \ldots, f(\log_e(625)) is equal to .
  24. Q24 · Numerical · ProbabilityOpen
    From the first 100 natural numbers, two numbers first aa and then bb are selected randomly without replacement. If the probability that a−b≥10a - b \ge 10 is mn\dfrac{m}{n}, gcd⁡(m,n)=1\gcd(m, n) = 1, then m+nm + n is equal to .
  25. The number of 4-letter words, with or without meaning, which can be formed using the letters PQRPQRSTUVP, is .