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PhysicsJEE Main 23 Jan 2026, Shift 1·Q3·MCQ·Easy

Electromagnetic Waves · EM waves

Match List-I with List-II.
List-I (Relation)List-II (Law)
A.∮E⃗⋅dl⃗=−ddt∮B⃗⋅da⃗\displaystyle\oint\vec E\cdot d\vec l = -\frac{d}{dt}\oint\vec B\cdot d\vec aI.Ampere's circuital law.
B.∮B⃗⋅dl⃗=μ0(I+ϵ0dϕEdt)\displaystyle\oint\vec B\cdot d\vec l = \mu_0\left(I + \epsilon_0\frac{d\phi_E}{dt}\right)II.Faraday's laws of electromagnetic induction.
(C)∮E⃗⋅da⃗=1ϵ0∫ρ dv\displaystyle\oint\vec E\cdot d\vec a = \frac{1}{\epsilon_0}\int\rho\,dvIII.Ampere-Maxwell law
(D)∮B⃗⋅dl⃗=μ0I\displaystyle\oint\vec B\cdot d\vec l = \mu_0 IIV.Gauss's law of electrostatics
Choose the correct answer from the options given below:
  1. (1)A-II, B-III, C-I, D-IV
  2. (2)A-II, B-III, C-IV, D-I
  3. (3)A-I, B-IV, C-III, D-II
  4. (4)A-IV, B-I, C-II, D-III
We corrected a printing error in the original paper

Source printed row B as “∮B⋅dl⃗=μ0(1+ϵ0dϕEdt)\oint B\cdot d\vec l = \mu_0\left(1 + \epsilon_0\frac{d\phi_E}{dt}\right)” (digit 1 for the current II, no arrow on BB).

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