3D Geometry · Image of a point in line

If the image of the point

P(a, 2, a)

in the line

\dfrac{x}{2} = \dfrac{y + a}{1} = \dfrac{z}{1}

Q

and the image of

Q

in the line

\dfrac{x - 2b}{2} = \dfrac{y - a}{1} = \dfrac{z + 2b}{-5}

P

, then

a + b

is equal to .

We corrected a printing error in the original paper

Source printed “and the of image of Q in the line”.

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