AktiraAktira JEE
PhysicsJEE Main 23 Jan 2026, Shift 2·Q1·MCQ·Moderate

Thermodynamics · Laws of thermodynamics

The internal energy of a gas is 3nRT. One mole of this gas is kept in a cylinder having internal cross section area of 17 cm217\ \mathrm{cm^2} and fitted with a light movable frictionless piston. The gas is heated slowly by supplying 126 J heat. If the temperature rises by 4 ∘4\ ^\circC, then the piston will move cm.
(atmospheric pressure =105= 10^{5} Pa)
  1. (1)14.5
  2. (2)1.55
  3. (3)15.5
  4. (4)1.45
We corrected a printing error in the original paper

Source printed “The internal energy of a monoatomic gas is 3nRT. One mole of helium is kept”; corrected to the intended “The internal energy of a gas is 3nRT. One mole of this gas is kept” (a monoatomic gas has U=32nRTU = \tfrac32 nRT, which gives 44.8 cm, no option; the key 15.5 uses U=3nRTU = 3nRT); “suppling”.

Video solution coming soon

We're animating every PYQ step by step. Subscribe to get them first.

Subscribe

See the full 23 Jan 2026, Shift 2 paper

More on Laws of thermodynamics