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PhysicsJEE Main 23 Jan 2026, Shift 2·Q17·MCQ·Moderate

Electromagnetic Induction · Induction laws

Suppose a long solenoid of 100 cm length, radius 2 cm having 500 turns per unit length, carries a current I=10sin⁡(ωt)I = 10\sin(\omega t) A, where ω=1000\omega = 1000 rad./s. A circular conducting loop (B) of radius 1 cm coaxially slid through the solenoid at a speed v=1v = 1 cm/s. The r.m.s. current through the loop when the coil B is inserted 10 cm inside the solenoid is α/2 μ\alpha/\sqrt2\ \muA. The value of α\alpha is .
[Resistance of the loop =10 Ω= 10\ \Omega]
  1. (1)197
  2. (2)80
  3. (3)280
  4. (4)100
We corrected a printing error in the original paper

Source printed “coaxially slided”.

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