Electric Potential and Capacitance · Potential energy

Two charges

7\ \mu

C and

-2\ \mu

C are placed at

(-9, 0, 0)

cm and

(9, 0, 0)

cm respectively in an external field

E = \dfrac{A}{r^2}\,\hat r

, where

A = 9\times10^{5}\ \mathrm{N\,m^2/C}

.
Considering the potential at infinity is 0, the electrostatic energy of the configuration is J.

We corrected a printing error in the original paper

Source printed the unit of $A$ as “ $\mathrm{N/C.m^2}$ ” ( $E = A/r^2$ needs $\mathrm{N\,m^2/C}$ ).

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