MathsJEE Main 24 Jan 2026, Shift 1·Q17·MCQ·Easy–moderate

Probability · Binomial distribution

From a lot containing 10 defective and 90 non-defective bulbs, 8 bulbs are selected one by one with replacement. Then the probability of getting at least 7 defective bulbs is :-

(1) $\dfrac{7}{10^7}$
(2) $\dfrac{81}{10^8}$
(3) $\dfrac{67}{10^8}$
(4) $\dfrac{73}{10^8}$

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