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JEE Main 2026

JEE Main 24 Jan 2026, Shift 1

75 questions. Answers are hidden — tap “Show answer” under each one.

Physics

  1. Match the List-I with List-II
    List-IList-II
    A.Magnetic inductionI.M L T−2A−2\mathrm{M\,L\,T^{-2}A^{-2}}
    B.Magnetic fluxII.M L2 T−2A−2\mathrm{M\,L^{2}\,T^{-2}A^{-2}}
    C.Magnetic permeabilityIII.M L0 T−2A−1\mathrm{M\,L^{0}\,T^{-2}A^{-1}}
    D.Self inductanceIV.M L2 T−2A−1\mathrm{M\,L^{2}\,T^{-2}A^{-1}}
    Choose the correct answer from the options given below:
    1. (1)(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
    2. (2)(A)-(III), (B)-(IV), (C)-(II), (D)-(I)
    3. (3)(A)-(I), (B)-(III), (C)-(IV), (D)-(II)
    4. (4)(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
  2. Three charges +2q+2q, +3q+3q and −4q-4q are situated at (0,−3a)(0, -3a), (2a,0)(2a, 0) and (−2a,0)(-2a, 0) respectively in the xyxy plane. The resultant dipole moment about origin is
    1. (1)2qa(3j^−i^)2qa\left(3\hat j - \hat i\right)
    2. (2)2qa(3i^−7j^)2qa\left(3\hat i - 7\hat j\right)
    3. (3)2qa(7i^−3j^)2qa\left(7\hat i - 3\hat j\right)
    4. (4)2qa(3j^−7i^)2qa\left(3\hat j - 7\hat i\right)
    We corrected a printing error in the original paper

    Source printed “+2q+2q. +3q+3q” (full stop for the comma).

  3. Q3 · MCQ · OscillationsOpen
    A cylindrical block of mass MM and area of cross section AA is floating in a liquid of density ρ\rho and with its axis vertical. When depressed a little and released the block starts oscillating. The period of oscillation is .
    1. (1)2πMρAg2\pi\sqrt{\dfrac{M}{\rho A g}}
    2. (2)π2MρAg\pi\sqrt{\dfrac{2M}{\rho A g}}
    3. (3)πρAMg\pi\sqrt{\dfrac{\rho A}{M g}}
    4. (4)2πρAMg2\pi\sqrt{\dfrac{\rho A}{M g}}
  4. Q4 · MCQ · ThermodynamicsOpen
    Density of water at 4∘4^\circC and 20∘20^\circC are 1000 kg/m31000\ \mathrm{kg/m^3} and 998 kg/m3998\ \mathrm{kg/m^3} respectively. The increase in internal energy of 4 kg water when it is heated from 4∘4^\circC to 20∘20^\circC is J.
    (Specific heat capacity of water =4.2 kJ kg−1 ∘C−1= 4.2\ \mathrm{kJ\,kg^{-1}\,{}^\circ C^{-1}} and 1 atmospheric pressure =105= 10^{5} Pa)
    1. (1)315826.2
    2. (2)234699.2
    3. (3)258700.8
    4. (4)268799.2
    We corrected a printing error in the original paper

    Source printed “1000 kg/m3^3 and respectively” and “4.2 J/kg.”; corrected to the intended “1000 kg/m3^3 and 998 kg/m3^3 respectively” and “4.2 kJ kg−1^{-1} ∘^\circC−1^{-1}” (the values the key uses).

  5. Two resistors of 100 Ω100\ \Omega each are connected in series with a 9 V battery. A voltmeter of 400 Ω400\ \Omega resistance is connected to measure the voltage drop across one of the resistors. The voltmeter reading is V.
    1. (1)3
    2. (2)4.5
    3. (3)4
    4. (4)2
  6. Q6 · MCQ · Ray OpticsOpen
    The exit surface of a prism with refractive index nn is coated with a material having refractive index n2\dfrac{n}{2}. When this prism is set for minimum angle of deviation it exactly meets the condition of critical angle. The prism angle is
    1. (1)60∘60^\circ
    2. (2)15∘15^\circ
    3. (3)30∘30^\circ
    4. (4)45∘45^\circ
  7. Q7 · MCQ · AtomsOpen
    Two electrons are moving in orbits of two hydrogen like atoms with speeds 3×1053\times10^{5} m/s and 2.5×1052.5\times10^{5} m/s respectively. If the radii of these orbits are nearly same then the possible orders of energy states are respectively.
    1. (1)6 and 5
    2. (2)9 and 8
    3. (3)8 and 10
    4. (4)10 and 12
    We corrected a printing error in the original paper

    Source printed “the possible order of energy states are”.

  8. Q8 · MCQ · Ray OpticsOpen
    In a microscope of tube length 10 cm two convex lenses are arranged with focal length of 2 cm and 5 cm. Total magnification obtained with this system for normal adjustment is (5)k(5)^{k}. The value of kk is
    1. (1)2
    2. (2)5
    3. (3)3.5
    4. (4)4
  9. For the series LCR circuit connected with 220 V, 50 Hz a.c source as shown in the figure, the power factor is α10\dfrac{\alpha}{10}. The value of α\alpha is
    1. (1)4
    2. (2)10
    3. (3)6
    4. (4)8
  10. Match the List-I with List-II
    List-IList-II
    ARadio-waveIis produced by Magnetron valve
    BMicro-waveIIDue to change in the vibrational modes of atoms
    CInfrared-waveIIIDue to inner shell electrons moving from higher energy level to lower energy level
    DX-rayIVDue to rapid acceleration of electrons
    Choose the correct answer from the options given below:
    1. (1)(A)-(II), (B)-(IV), (C)-(III), (D)-(I)
    2. (2)(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
    3. (3)(A)-(IV), (B)-(I), (C)-(II), (D)-(III)
    4. (4)(A)-(IV), (B)-(II), (C)-(I), (D)-(III)
    We corrected a printing error in the original paper

    Source printed “Magnetron value”.

  11. Q11 · MCQ · OscillationsOpen
    A spring of force constant 15 N/m is cut into two pieces. If the ratio of their length is 1:31:3, then the force constant of smaller piece is N/m
    1. (1)15
    2. (2)20
    3. (3)60
    4. (4)45
  12. Two resistors 2 Ω2\ \Omega and 3 Ω3\ \Omega are connected in the gaps of bridge as shown in figure. The null point is obtained with the contact of jockey at some point on wire XY. When an unknown resistor is connected in parallel with 3 Ω3\ \Omega resistor, the null point is shifted by 22.5 cm toward Y. The resistance of unknown resistor is Ω\Omega. (Take the length of the wire XY as 100 cm)
    1. (1)3
    2. (2)2
    3. (3)4
    4. (4)1
    We corrected a printing error in the original paper

    Assumption “(Take the length of the wire XY as 100 cm)” added; the source leaves it unstated.

  13. Q13 · MCQ · NucleiOpen
    Given below are two statements:
    Statement I : For all elements, greater the mass of the nucleus, greater is the binding energy per nucleon.
    Statement II : For all elements, nuclei with less binding energy per nucleon transform to nuclei with greater binding energy per nucleon.
    In the light of the above statements, choose the correct answer from the options given below:
    1. (1)Both Statement I and Statement II are true
    2. (2)Statement I is true but Statement II is false
    3. (3)Both Statement I and Statement II are false
    4. (4)Statement I is false but Statement II is true
    We corrected a printing error in the original paper

    Source printed “nuclei with less binding energy per nucleon transforms”.

  14. A brass wire of length 2 m and radius 1 mm at 27∘27^\circC is held taut between two rigid supports. Initially it was cooled to a temperature of −43∘-43^\circC creating a tension TT in the wire. The temperature to which the wire has to be cooled in order to increase the tension in it to 1.4T1.4T, is ∘^\circC
    1. (1)−86-86
    2. (2)−71-71
    3. (3)−65-65
    4. (4)−80-80
  15. The electrostatic potential in a charged spherical region of radius rr varies as V=ar3+bV = ar^{3} + b, where aa and bb are constants. The total charge in the sphere of unit radius is α×πaϵ0\alpha\times\pi a\epsilon_0. The value of α\alpha is .
    (permittivity of vacuum is ϵ0\epsilon_0)
    1. (1)−12-12
    2. (2)−6-6
    3. (3)−9-9
    4. (4)−8-8
  16. Two masses 400 g and 350 g are suspended from the ends of a light string passing over a heavy pulley of radius 2 cm. When released from rest the heavier mass is observed to fall 81 cm in 9 s. The rotational inertia of the pulley is kg.m2\mathrm{kg.m^2}.
    (g=9.8 m/s2g = 9.8\ \mathrm{m/s^2})
    1. (1)9.5×10−39.5\times10^{-3}
    2. (2)4.75×10−34.75\times10^{-3}
    3. (3)1.86×10−21.86\times10^{-2}
    4. (4)8.3×10−38.3\times10^{-3}
  17. Q17 · MCQ · Wave OpticsOpen
    An unpolarised light is incident at an interface of two dielectric media having refractive indices of 2 (incident medium) and 232\sqrt3 (medium) respectively. To satisfy the condition that reflected and refracted rays are perpendicular to each other, the angle of incidence is .
    1. (1)60∘60^\circ
    2. (2)10∘10^\circ
    3. (3)30∘30^\circ
    4. (4)45∘45^\circ
  18. A boy throws a ball into air at 45∘45^\circ from the horizontal to land it on a roof of a building of height HH. If the ball attains maximum height in 2 s and lands on the building in 3 s after launch, then value of HH is m.
    (g=10 m/s2g = 10\ \mathrm{m/s^2})
    1. (1)20
    2. (2)10
    3. (3)25
    4. (4)15
    We corrected a printing error in the original paper

    Source printed “A boy thrown a ball”.

  19. There are three concentric conducting spherical shells A, B and C of radii aa, bb and cc carrying charges q1q_1, q2q_2 and q3q_3 respectively. The potential of the spheres A, B and C respectively, are :
    1. (1)14πϵ0(q1+q2+q3a), 14πϵ0(q1+q2+q3b), 14πϵ0(q1+q2+q3c)\dfrac{1}{4\pi\epsilon_0}\left(\dfrac{q_1+q_2+q_3}{a}\right),\ \dfrac{1}{4\pi\epsilon_0}\left(\dfrac{q_1+q_2+q_3}{b}\right),\ \dfrac{1}{4\pi\epsilon_0}\left(\dfrac{q_1+q_2+q_3}{c}\right)
    2. (2)14πϵ0(q1+q2+q3a), 14πϵ0(q1+q2b+q3c), 14πϵ0(q1a+q2b+q3c)\dfrac{1}{4\pi\epsilon_0}\left(\dfrac{q_1+q_2+q_3}{a}\right),\ \dfrac{1}{4\pi\epsilon_0}\left(\dfrac{q_1+q_2}{b}+\dfrac{q_3}{c}\right),\ \dfrac{1}{4\pi\epsilon_0}\left(\dfrac{q_1}{a}+\dfrac{q_2}{b}+\dfrac{q_3}{c}\right)
    3. (3)14πϵ0(q1a+q2b+q3c), 14πϵ0(q1+q2b+q3c), 14πϵ0(q1+q2+q3c)\dfrac{1}{4\pi\epsilon_0}\left(\dfrac{q_1}{a}+\dfrac{q_2}{b}+\dfrac{q_3}{c}\right),\ \dfrac{1}{4\pi\epsilon_0}\left(\dfrac{q_1+q_2}{b}+\dfrac{q_3}{c}\right),\ \dfrac{1}{4\pi\epsilon_0}\left(\dfrac{q_1+q_2+q_3}{c}\right)
    4. (4)14πϵ0(q1a+q2b+q3c), 14πϵ0(q1+q2+q3b), 14πϵ0(q1+q2+q3c)\dfrac{1}{4\pi\epsilon_0}\left(\dfrac{q_1}{a}+\dfrac{q_2}{b}+\dfrac{q_3}{c}\right),\ \dfrac{1}{4\pi\epsilon_0}\left(\dfrac{q_1+q_2+q_3}{b}\right),\ \dfrac{1}{4\pi\epsilon_0}\left(\dfrac{q_1+q_2+q_3}{c}\right)
    We corrected a printing error in the original paper

    Source printed “three co-centric conducting spherical shells A, B and C of radii aa, bb and cc respectively” (the charges used in the options are never stated); corrected to the intended “three concentric conducting spherical shells A, B and C of radii aa, bb and cc carrying charges q1q_1, q2q_2 and q3q_3 respectively”.

  20. Q20 · MCQ · GravitationOpen
    Three masses 200 kg, 300 kg and 400 kg are placed at the vertices of an equilateral triangle with sides 20 m. They are rearranged on the vertices of a bigger triangle of side 25 m and with the same centre. The work done in this process is J.
    (Gravitational constant G=6.7×10−11 N m2/kg2G = 6.7\times10^{-11}\ \mathrm{N\,m^2/kg^2})
    1. (1)9.86×10−69.86\times10^{-6}
    2. (2)2.85×10−72.85\times10^{-7}
    3. (3)1.74×10−71.74\times10^{-7}
    4. (4)4.77×10−74.77\times10^{-7}
    We corrected a printing error in the original paper

    Source printed “The work done in this process ___ J” (“is” missing).

  21. Q21 · Numerical · Magnetism and MatterOpen
    A short bar magnet placed with its axis at 30∘30^\circ with an external field of 800 Gauss, experiences a torque of 0.016 N.m. The work done in moving it from most stable to most unstable position is α×10−3\alpha\times10^{-3} J. The value of α\alpha is .
  22. Q22 · Numerical · Kinetic Theory of GasesOpen
    A gas of certain mass filled in a closed cylinder at a pressure of 3.23 kPa has temperature 50∘50^\circC. The gas is now heated to 100∘100^\circC. The modified pressure is Pa.
    We corrected a printing error in the original paper

    Source printed “heated to double its temperature”; reworded to “heated to 100∘100^\circC”, the reading behind the NTA key 3730 (doubling the absolute temperature would give 6460 Pa).

  23. Q23 · Numerical · Semiconductor ElectronicsOpen
    A voltage regulating circuit consisting of Zener diode, having break-down voltage of 10 V and maximum power dissipation of 0.4 W, is operated at 15 V. The approximate value of protective resistance in this circuit is Ω\Omega.
  24. Q24 · Numerical · Newton's Laws of MotionOpen
    In the given figure the blocks A, B and C weigh 4 kg, 6 kg and 8 kg respectively. The co-efficient of sliding friction between any two surfaces is 0.5. The force F⃗\vec F required to slide the block C with constant speed is N. (Use g=10 m/s2g = 10\ \mathrm{m/s^2})
    We corrected a printing error in the original paper

    Answer corrected; the source key is (210) — it holds A fixed (friction 20 N on A), but in the figure A rests free on B and moves with it: T=50T = 50 N, F=90+50+50=190F = 90 + 50 + 50 = 190 N; source printed “(Used g=10 m/s2g = 10\ \mathrm{m/s^2})”.

  25. Sixty four rain drops of radius 1 mm each falling down with a terminal velocity of 10 cm/s coalesce to form a bigger drop. The terminal velocity of bigger drop is cm/s.

Chemistry

  1. Given below are two statements :

    Statement-I Hybridisation, shape and spin only magnetic moment of KX3[Co(COX3)X3]\ce{K3[Co(CO3)3]} are sp3^3d2^2, octahedral and 4.9 BM respectively.

    Statement-II Geometry, hybridisation and spin only magnetic moment values (BM) of the ions [Ni(CN)X4]X2−\ce{[Ni(CN)4]^{2-}}, [MnBrX4]X2−\ce{[MnBr4]^{2-}} and [CoFX6]X3−\ce{[CoF6]^{3-}} respectively are square planar, tetrahedral, octahedral : dsp2^2, sp3^3, sp3^3d2^2 and 0, 5.9, 4.9.

    In the light of the above statements, choose the correct answer from the options given below

    1. (1)Both statement-I and statement-II are false
    2. (2)Statement I is false but statement-II is true
    3. (3)Both statement-I and statement-II are true
    4. (4)Statement-I is true but statement-II is false
    We corrected a printing error in the original paper

    Answer corrected; the source key is (3) — [Co(COX3)X3]X3−\ce{[Co(CO3)3]^{3-}} is a low-spin Co(III) (d6^6) complex like [Co(CX2OX4)X3]X3−\ce{[Co(C2O4)3]^{3-}}: d2^2sp3^3, diamagnetic (0 BM), so Statement-I is false and Statement-II is true; also source printed “spin only magnetic moment of KX3[Co(COX3)X3]\ce{K3[Co(CO3)3]} is”.

  2. A→D\ce{A -> D} is an endothermic reaction occurring in three steps (elementary).

    (i) A→B\ce{A -> B} ΔHi=+\Delta H_\mathrm{i} = +ve

    (ii) B→C\ce{B -> C} ΔHii=−\Delta H_\mathrm{ii} = -ve

    (iii) C→D\ce{C -> D} ΔHiii=−\Delta H_\mathrm{iii} = -ve

    Which of the following graphs between potential energy (y-axis) vs reaction coordinate (x-axis) correctly represents the reaction profile of A→D\ce{A -> D} ?

    1. (1)
    2. (2)
    3. (3)
    4. (4)
  3. Q3 · MCQ · HydrocarbonsOpen
    Arrange the following alkenes in decreasing order of stability.
    Choose the correct answer from the options given below :
    1. (1)III >> I >> II >> IV
    2. (2)III >> II >> I >> IV
    3. (3)I >> III >> II >> IV
    4. (4)I >> III >> IV >> II
  4. Given below are statements about some molecules/ions.

    Identify the CORRECT statements.

    • (A)The dipole moment value of NFX3\ce{NF3} is higher than that of NHX3\ce{NH3}.
    • (B)The dipole moment value of BeHX2\ce{BeH2} is zero.
    • (C)The bond order of OX2X2−\ce{O2^{2-}} and FX2\ce{F2} is same.
    • (D)The formal charge on the central oxygen atom of ozone is −1-1.
    • (E)In NOX2\ce{NO2}, all the three atoms satisfy the octet rule, hence it is very stable.
    Choose the correct answer from the options given below :
    1. (1)A, B, C, D & E
    2. (2)B & C only
    3. (3)B, C & D only
    4. (4)A, C & D only
  5. Q5 · MCQ · SolutionsOpen

    A solution is prepared by dissolving 0.3 g of a non-volatile non-electrolyte solute ‘A' of molar mass 60 g mol−1^{-1} and 0.9 g of a non-volatile non-electrolyte solute ‘B' of molar mass 180 g mol−1^{-1} in 100 mL HX2O\ce{H2O} at 27∘^\circC. Osmotic pressure of the solution will be

    [Given : R=0.082R = 0.082 L atm K−1^{-1} mol−1^{-1}]

    1. (1)1.23 atm
    2. (2)2.46 atm
    3. (3)0.82 atm
    4. (4)1.47 atm
  6. Among the following, the CORRECT combinations are :
    • (A)IFX3\ce{IF3} →\rightarrow T-shaped (sp3^3d)
    • (B)IFX5\ce{IF5} →\rightarrow Square pyramidal (sp3^3d2^2)
    • (C)IFX7\ce{IF7} →\rightarrow Pentagonal bipyramidal (sp3^3d3^3)
    • (D)ClOX4X−\ce{ClO4^-} →\rightarrow Square planar (sp2^2d)
    Choose the correct answer from the options given below :
    1. (1)A, B and C only
    2. (2)A and B only
    3. (3)A, B, C and D
    4. (4)B, C and D Only
  7. Q7 · MCQ · AminesOpen
    The correct stability order of the following diazonium salts is
    1. (1)A >> B >> C >> D
    2. (2)C >> D >> B >> A
    3. (3)A >> C >> D >> B
    4. (4)C >> A >> D >> B
  8. Consider a mixture ‘X' which is made by dissolving 0.4 mol of [Co(NHX3)X5SOX4]Br\ce{[Co(NH3)5SO4]Br} and 0.4 mol of [Co(NHX3)X5Br]SOX4\ce{[Co(NH3)5Br]SO4} in water to make 4 L of solution. When 2 L of mixture ‘X' is allowed to react with excess of AgNOX3\ce{AgNO3}, it forms precipitate ‘Y'. The rest 2 L of mixture ‘X' reacts with excess BaClX2\ce{BaCl2} to form precipitate ‘Z'. Which of the following statements is CORRECT.
    1. (1)0.2 mol of ‘Z' is formed
    2. (2)‘Y' is BaSOX4\ce{BaSO4} and ‘Z' is AgBr
    3. (3)0.4 mol of ‘Z' is formed
    4. (4)0.1 mol of ‘Y' is formed
  9. Given below are two statements

    Statement-I : The number of paramagnetic species among [CoFX6]X3−\ce{[CoF6]^{3-}}, [TiFX6]X3−\ce{[TiF6]^{3-}}, VX2OX5\ce{V2O5} and [Fe(CN)X6]X3−\ce{[Fe(CN)6]^{3-}} is 3.

    Statement-II : KX4[Fe(CN)X6]\ce{K4[Fe(CN)6]} << KX3[Fe(CN)X6]\ce{K3[Fe(CN)6]} << [Fe(HX2O)X6]SOX4 ⋅ HX2O\ce{[Fe(H2O)6]SO4.H2O} << [Fe(HX2O)X6]ClX3\ce{[Fe(H2O)6]Cl3} is the correct order in terms of number of unpaired electron(s) in the complexes.

    In the light of the above statements, choose the correct answer from the options given below.

    1. (1)Both statement-I and statement-II are true
    2. (2)Both statement-I and statement-II are false
    3. (3)Statement-I is true but statement-II is false
    4. (4)Statement-I is false but statement-II is true
    We corrected a printing error in the original paper

    Source printed “Statements-I :”.

  10. Consider three metal chlorides x, y and z, where x is water soluble at room temperature, y is sparingly soluble in water at room temperature and z is soluble in hot water. x, y and z are respectively
    1. (1)MgClX2\ce{MgCl2}, AgCl and AlClX3\ce{AlCl3}
    2. (2)AgCl, HgX2ClX2\ce{Hg2Cl2} and PbClX2\ce{PbCl2}
    3. (3)AlClX3\ce{AlCl3}, PbClX2\ce{PbCl2} and BaClX2\ce{BaCl2}
    4. (4)CuClX2\ce{CuCl2}, AgCl and PbClX2\ce{PbCl2}
  11. Match the List-I with List-II
    List-IList-II
    (Chloro derivative)(Example)
    A.Vinyl ChlorideI.CHX2=CH−CHX2Cl\ce{CH2=CH-CH2Cl}
    B.Benzyl chlorideII.CHX3−CH(Cl)CHX3\ce{CH3-CH(Cl)CH3}
    C.Alkyl chlorideIII.CHX2=CHCl\ce{CH2=CHCl}
    D.Allyl chlorideIV.
    Choose the correct answer from the options given below :
    1. (1)A-IV, B-I, C-III, D-II
    2. (2)A-III, B-IV, C-I, D-II
    3. (3)A-III, B-IV, C-II, D-I
    4. (4)A-I, B-II, C-IV, D-III
    We corrected a printing error in the original paper

    List-II entry II: source printed “CH3_3 = CH(Cl)CH3_3” (a double bond on a CH3_3 carbon); corrected to the intended alkyl chloride “CH3_3–CH(Cl)CH3_3” (2-chloropropane).

  12. Q12 · MCQ · SolutionsOpen

    ‘W' g of a non-volatile electrolyte solid solute of molar mass ‘M' g mol−1^{-1} when dissolved in 100 mL water, decreases vapour pressure of water from 640 mm Hg to 600 mm Hg. If aqueous solution of the electrolyte boils at 375 K and KbK_\mathrm{b} for water is 0.52 K kg mol−1^{-1}, then the mole fraction of the electrolyte solute (x2x_2) in the solution can be expressed as

    (Given : density of water = 1 g/mL and boiling point of water = 373 K)

    1. (1)1.38×WM\dfrac{1.3}{8}\times\dfrac{\mathrm{W}}{\mathrm{M}}
    2. (2)162.6×WM\dfrac{16}{2.6}\times\dfrac{\mathrm{W}}{\mathrm{M}}
    3. (3)2.616×MW\dfrac{2.6}{16}\times\dfrac{\mathrm{M}}{\mathrm{W}}
    4. (4)1.38×MW\dfrac{1.3}{8}\times\dfrac{\mathrm{M}}{\mathrm{W}}
  13. Q13 · MCQ · ThermodynamicsOpen
    Match the List-I with List-II
    List-IList-II
    (Isothermal processWork done (Vf>Vi\boldsymbol{V_\mathrm{f} > V_\mathrm{i}})
    for ideal gas system)
    A.Reversible expansionI.w=0w = 0
    B.Free expansionII.w=−nRTln⁡VfViw = -nRT\ln\dfrac{V_\mathrm{f}}{V_\mathrm{i}}
    C.Irreversible expansionIII.w=−pex (Vf−Vi)w = -p_\mathrm{ex}\,(V_\mathrm{f} - V_\mathrm{i})
    D.Irreversible compressionIV.w=−pex (Vi−Vf)w = -p_\mathrm{ex}\,(V_\mathrm{i} - V_\mathrm{f})
    Choose the correct answer from the options given below :
    1. (1)A-IV, B-I, C-III, D-II
    2. (2)A-IV, B-II, C-III, D-I
    3. (3)A-I, B-III, C-II, D-IV
    4. (4)A-II, B-I, C-III, D-IV
  14. A student is given one compound among the following compounds that gives positive test with Tollen's reagent.
    The compound is :
    1. (1)D
    2. (2)A
    3. (3)B
    4. (4)C
  15. A hydroxy compound (X) with molar mass 122 g mol−1^{-1} is acetylated with acetic anhydride, using a large excess of the reagent ensuring complete acetylation of all hydroxyl groups. The product obtained has a molar mass of 290 g mol−1^{-1}. The number of hydroxyl groups present in compound (X) is :
    1. (1)3
    2. (2)5
    3. (3)2
    4. (4)4
  16. At 27∘^\circC in presence of a catalyst, activation energy of a reaction is lowered by 10 kJ mol−1^{-1}. The logarithm ratio of k(catalysed)k(uncatalysed)\dfrac{k(\text{catalysed})}{k(\text{uncatalysed})} is ….

    (Consider that the frequency factor for both the reactions is same)

    1. (1)17.41
    2. (2)1.741
    3. (3)3.482
    4. (4)0.1741
  17. Given below are two statements :

    Statement I : ‘C–Cl' bond is stronger in CHX2=CH−Cl\ce{CH2=CH-Cl} than CHX3−CHX2−Cl\ce{CH3-CH2-Cl}

    Statement II : The given optically active molecule,

    on hydrolysis gives a solution that can rotate the plane polarized light.

    In the light of the above statements, choose the correct answer from the options given below

    1. (1)Statement I is false but Statement II is true
    2. (2)Both Statement I and Statement II are true
    3. (3)Both Statement I and Statement II are false
    4. (4)Statement I is true but Statement II is false
  18. Consider the following two reactions A and B.
    Numerical value of [molar mass of x ++ molar mass of y] is .
    1. (1)4
    2. (2)88
    3. (3)46
    4. (4)160
  19. Arrange the following carbanions in the decreasing order of stability
    • (I)pp–Br–CX6HX4\ce{C6H4}–C¨⊖H2\overset{\ominus}{\ddot{\mathrm{C}}}\mathrm{H_2}
    • (II)CX6HX5\ce{C6H5}–C¨⊖H2\overset{\ominus}{\ddot{\mathrm{C}}}\mathrm{H_2}
    • (III)pp–CHX3O\ce{CH3O}–CX6HX4\ce{C6H4}–C¨⊖H2\overset{\ominus}{\ddot{\mathrm{C}}}\mathrm{H_2}
    • (IV)pp–CHO–CX6HX4\ce{C6H4}–C¨⊖H2\overset{\ominus}{\ddot{\mathrm{C}}}\mathrm{H_2}
    • (V)pp–CHX3\ce{CH3}–CX6HX4\ce{C6H4}–C¨⊖H2\overset{\ominus}{\ddot{\mathrm{C}}}\mathrm{H_2}
    Choose the correct answer from the options given below :
    1. (1)I >> II >> IV >> V >> III
    2. (2)I >> IV >> II >> V >> III
    3. (3)IV >> I >> II >> V >> III
    4. (4)IV >> II >> I >> III >> V
  20. Given below are two statements :

    Statement I : K >> Mg >> Al >> B is the correct order in terms of metallic character.

    Statement II : Atomic radius is always greater than the ionic radius for any element.

    In the light of the above statements, choose the correct answer from the options given below

    1. (1)Both Statement I and Statement II are true
    2. (2)Both Statement I and Statement II are false
    3. (3)Statement I is false but Statement II is true
    4. (4)Statement I is true but Statement II is false
  21. Q21 · Numerical · ElectrochemistryOpen

    Electricity is passed through an acidic solution of CuX2+\ce{Cu^{2+}} till all the CuX2+\ce{Cu^{2+}} was exhausted, leading to the deposition of 300 mg of Cu metal. However, a current of 600 mA was continued to pass through the same solution for another 28 minutes by keeping the total volume of the solution fixed at 200 mL. The total volume of oxygen evolved at STP during the entire process is mL. (Nearest integer)

    [Given :

    CuX2+(aq)+2 eX−→Cu(s)\ce{Cu^{2+}(aq) + 2e^- -> Cu(s)}   Ered0=+0.34E^0_\mathrm{red} = +0.34 V

    OX2(g)+4 HX++4 eX−→2 HX2O\ce{O2(g) + 4H^+ + 4e^- -> 2H2O}   Ered0=+1.23E^0_\mathrm{red} = +1.23 V

    Molar mass of Cu = 63.54 g mol−1^{-1}

    Molar mass of OX2\ce{O2} = 32 g mol−1^{-1}

    Faraday Constant = 96500 C mol−1^{-1}

    Molar volume at STP = 22.4 L ]

    We corrected a printing error in the original paper

    Source printed “till all the cu2+^{2+} was exhausted”.

  22. Q22 · Numerical · EquilibriumOpen

    Consider two Group IV metal ions XX2+\ce{X^{2+}} and YX2+\ce{Y^{2+}}.

    A solution containing 0.01 M XX2+\ce{X^{2+}} and 0.01 M YX2+\ce{Y^{2+}} is saturated with HX2S\ce{H2S}. The pH at which the metal sulphide YS will form as a precipitate is (Nearest integer)

    (Given :

    Ksp(XS)=1×10−22K_\mathrm{sp}(\mathrm{XS}) = 1\times10^{-22} at 25∘^\circC, Ksp(YS)=4×10−16K_\mathrm{sp}(\mathrm{YS}) = 4\times10^{-16} at 25∘^\circC,

    [HX2S\ce{H2S}] = 0.1 M in solution, Ka1×Ka2K_\mathrm{a1}\times K_\mathrm{a2} (HX2S\ce{H2S}) =1.0×10−21= 1.0\times10^{-21},

    log⁡2=0.30\log 2 = 0.30, log⁡3=0.48\log 3 = 0.48, log⁡5=0.70\log 5 = 0.70)

  23. Q23 · Numerical · Structure of AtomOpen
    The hydrogen spectrum consists of several spectral lines in Lyman series (L1L_1, L2L_2, L3L_3 …; L1L_1 has lowest energy among Lyman series). Similarly it consists of several spectral lines in Balmer series (B1B_1, B2B_2, B3B_3 …; B1B_1 has lowest energy among Balmer lines). The energy of L1L_1 is xx times the energy of B1B_1. The value of xx is × 10−1\times\,10^{-1} (Nearest integer)
    We corrected a printing error in the original paper

    Source printed “(Nearest inteter)”.

  24. In Dumas method for estimation of nitrogen, 0.50 g of an organic compound gave 70 mL of nitrogen collected at 300 K and 715 mm pressure. The percentage of nitrogen in the organic compound is %

    (Aqueous tension at 300 K is 15 mm).

  25. Q25 · Numerical · Redox ReactionsOpen

    X and Y are the number of electrons involved, respectively during the oxidation of IX−\ce{I^-} to IX2\ce{I2} and SX2−\ce{S^{2-}} to S by acidified KX2CrX2OX7\ce{K2Cr2O7}. The value of X + Y is .

    (Consider the electrons transferred per mole of KX2CrX2OX7\ce{K2Cr2O7} reduced in each reaction)

    We corrected a printing error in the original paper

    Assumption “(Consider the electrons transferred per mole of KX2CrX2OX7\ce{K2Cr2O7} reduced in each reaction)” added; the source leaves it unstated (per IX2\ce{I2}/S formed it would be 2 + 2 = 4).

Maths

  1. If the function f(x)=ex(etan⁡x−x−1)+log⁡e(sec⁡x+tan⁡x)−xtan⁡x−xf(x) = \dfrac{e^x\left(e^{\tan x - x} - 1\right) + \log_e(\sec x + \tan x) - x}{\tan x - x} is Continuous at x=0x = 0, then the value of f(0)f(0) is equal to
    1. (1)2
    2. (2)23\dfrac23
    3. (3)12\dfrac12
    4. (4)32\dfrac32
  2. Q2 · MCQ · CirclesOpen
    Let a circle of radius 4 pass through the origin OO, the points A(−3 a,0)A\left(-\sqrt3\,a, 0\right) and B(0,−2 b)B\left(0, -\sqrt2\,b\right), where aa and bb are real parameters and ab≠0ab \neq 0. Then the locus of the centroid of ΔOAB\Delta OAB is a circle of radius
    1. (1)53\dfrac53
    2. (2)73\dfrac73
    3. (3)83\dfrac83
    4. (4)113\dfrac{11}{3}
  3. Q3 · MCQ · 3D GeometryOpen
    Let the lines L1:r⃗=i^+2j^+3k^+λ(2i^+3j^+4k^)L_1 : \vec r = \hat i + 2\hat j + 3\hat k + \lambda\left(2\hat i + 3\hat j + 4\hat k\right), λ∈R\lambda \in \mathbb{R} and L2:r⃗=(4i^+j^)+μ(5i^+2j^+k^)L_2 : \vec r = \left(4\hat i + \hat j\right) + \mu\left(5\hat i + 2\hat j + \hat k\right), μ∈R\mu \in \mathbb{R}, intersect at the point RR. Let PP and QQ be the points lying on lines L1L_1 and L2L_2, respectively, such that ∣PR→∣=29\left\lvert\overrightarrow{PR}\right\rvert = \sqrt{29} and ∣PQ→∣=473\left\lvert\overrightarrow{PQ}\right\rvert = \sqrt{\dfrac{47}{3}}. If the point PP lies in the first octant, then 27(QR)227(QR)^2 is equal to
    1. (1)340
    2. (2)360
    3. (3)320
    4. (4)348
  4. Let 729,81,9,1,…729, 81, 9, 1, \ldots be a sequence and PnP_n denote the product of the first nn terms of this sequence. If 2∑n=140(Pn)1n=3α−13β2\sum_{n=1}^{40}\left(P_n\right)^{\frac1n} = \dfrac{3^{\alpha} - 1}{3^{\beta}} and gcd⁡(α,β)=1\gcd(\alpha, \beta) = 1, then α+β\alpha + \beta is equal to
    1. (1)73
    2. (2)74
    3. (3)75
    4. (4)76
  5. Q5 · MCQ · VectorsOpen
    Let a⃗=2i^+j^−2k^\vec a = 2\hat i + \hat j - 2\hat k, b⃗=i^+j^\vec b = \hat i + \hat j and c⃗=a⃗×b⃗\vec c = \vec a \times \vec b. Let d⃗\vec d be a vector such that ∣d⃗−a⃗∣=11\lvert\vec d - \vec a\rvert = \sqrt{11}, ∣c⃗×d⃗∣=3\lvert\vec c \times \vec d\rvert = 3 and the angle between c⃗\vec c and d⃗\vec d is π4\dfrac{\pi}{4}. Then a⃗⋅d⃗\vec a \cdot \vec d is equal to
    1. (1)11
    2. (2)3
    3. (3)0
    4. (4)1
  6. If the domain of the function f(x)=log⁡(10x2−17x+7)(18x2−11x+1)f(x) = \log_{(10x^2 - 17x + 7)}\left(18x^2 - 11x + 1\right) is (−∞,a)∪(b,c)∪(d,∞)−{e}(-\infty, a) \cup (b, c) \cup (d, \infty) - \{e\}, then 90(a+b+c+d+e)90(a + b + c + d + e) equals:
    1. (1)170
    2. (2)177
    3. (3)307
    4. (4)316
  7. Q7 · MCQ · Conic SectionsOpen
    Let each of the two ellipses E1:x2a2+y2b2=1E_1 : \dfrac{x^2}{a^2} + \dfrac{y^2}{b^2} = 1, (a>b)(a > b) and E2:x2A2+y2B2=1E_2 : \dfrac{x^2}{A^2} + \dfrac{y^2}{B^2} = 1, (A<B)(A < B) have eccentricity 45\dfrac45. Let the lengths of the latus recta of E1E_1 and E2E_2 be ℓ1\ell_1 and ℓ2\ell_2, respectively, such that 2ℓ12=9ℓ22\ell_1^2 = 9\ell_2. If the distance between the foci of E1E_1 is 8, then the distance between the foci of E2E_2 is
    1. (1)965\dfrac{96}{5}
    2. (2)325\dfrac{32}{5}
    3. (3)165\dfrac{16}{5}
    4. (4)85\dfrac85
  8. Q8 · MCQ · TrigonometryOpen
    The value of 3cosec⁡20∘−sec⁡20∘cos⁡20∘cos⁡40∘cos⁡60∘cos⁡80∘\dfrac{\sqrt3\operatorname{cosec}20^\circ - \sec20^\circ}{\cos20^\circ\cos40^\circ\cos60^\circ\cos80^\circ} is equal to
    1. (1)32
    2. (2)16
    3. (3)64
    4. (4)12
  9. Let S={z∈C:∣z−6iz−2i∣=1 and ∣z−8+2iz+2i∣=35}S = \left\{z \in \mathbb{C} : \left\lvert\dfrac{z - 6i}{z - 2i}\right\rvert = 1 \text{ and } \left\lvert\dfrac{z - 8 + 2i}{z + 2i}\right\rvert = \dfrac35\right\}. Then ∑z∈S∣z∣2\displaystyle\sum_{z \in S}\lvert z\rvert^2 is equal to
    1. (1)398
    2. (2)413
    3. (3)423
    4. (4)385
    We corrected a printing error in the original paper

    Source printed the summation index as “z∈sz \in s” (lower-case ss; the set is SS).

  10. Q10 · MCQ · TrigonometryOpen
    If cot⁡x=512\cot x = \dfrac{5}{12} for some x∈(π,3π2)x \in \left(\pi, \dfrac{3\pi}{2}\right), then sin⁡7x(cos⁡13x2+sin⁡13x2)+cos⁡7x(cos⁡13x2−sin⁡13x2)\sin7x\left(\cos\dfrac{13x}{2} + \sin\dfrac{13x}{2}\right) + \cos7x\left(\cos\dfrac{13x}{2} - \sin\dfrac{13x}{2}\right) is equal to
    1. (1)426\dfrac{4}{\sqrt{26}}
    2. (2)626\dfrac{6}{\sqrt{26}}
    3. (3)113\dfrac{1}{\sqrt{13}}
    4. (4)513\dfrac{5}{\sqrt{13}}
  11. Let f(t)=∫(1−sin⁡(log⁡et)1−cos⁡(log⁡et))dtf(t) = \displaystyle\int\left(\dfrac{1 - \sin(\log_e t)}{1 - \cos(\log_e t)}\right)dt, t>1t > 1. If f(eπ/2)=−eπ/2f\left(e^{\pi/2}\right) = -e^{\pi/2} and f(eπ/4)=α eπ/4f\left(e^{\pi/4}\right) = \alpha\, e^{\pi/4}, then α\alpha equals
    1. (1)−1−2-1 - \sqrt2
    2. (2)−1−22-1 - 2\sqrt2
    3. (3)1+21 + \sqrt2
    4. (4)−1+2-1 + \sqrt2
  12. Let RR be a relation defined on the set {1,2,3,4}×{1,2,3,4}\{1, 2, 3, 4\} \times \{1, 2, 3, 4\} by R={((a,b),(c,d)):2a+3b=3c+4d}.R = \{((a, b), (c, d)) : 2a + 3b = 3c + 4d\}. Then the number of elements in RR is
    1. (1)6
    2. (2)18
    3. (3)12
    4. (4)15
  13. Q13 · MCQ · Straight LinesOpen
    Let A(1,0)A(1, 0), B(2,−1)B(2, -1) and C(73,43)C\left(\dfrac73, \dfrac43\right) be three points. If the equation of the bisector of the angle ABCABC is αx+βy=5\alpha x + \beta y = 5, then the value of α2+β2\alpha^2 + \beta^2 is
    1. (1)8
    2. (2)5
    3. (3)13
    4. (4)10
  14. Q14 · MCQ · Binomial TheoremOpen
    Let S=125!+13! 23!+15! 21!+…S = \dfrac{1}{25!} + \dfrac{1}{3!\,23!} + \dfrac{1}{5!\,21!} + \ldots up to 13 terms. If 13S=2kn!13S = \dfrac{2^k}{n!}, k∈Nk \in \mathbb{N}, then n+kn + k is equal to
    1. (1)51
    2. (2)52
    3. (3)49
    4. (4)50
  15. Consider an A.P.: a1,a2,…,ana_1, a_2, \ldots, a_n; a1>0a_1 > 0. If a2−a1=−34a_2 - a_1 = \dfrac{-3}{4}, an=14a1a_n = \dfrac14 a_1, and ∑i=1nai=5252\displaystyle\sum_{i=1}^{n} a_i = \dfrac{525}{2}, then ∑i=117ai\displaystyle\sum_{i=1}^{17} a_i is equal to
    1. (1)476
    2. (2)952
    3. (3)238
    4. (4)136
  16. Let α,β∈R\alpha, \beta \in \mathbb{R} be such that the function f(x)={2α(x2−2)+2βx,x<1(α+3)x+(α−β),x≥1f(x) = \begin{cases} 2\alpha(x^2 - 2) + 2\beta x, & x < 1\\ (\alpha + 3)x + (\alpha - \beta), & x \ge 1\end{cases} be differentiable at all x∈Rx \in \mathbb{R}. Then 34(α+β)34(\alpha + \beta) is equal to
    1. (1)84
    2. (2)48
    3. (3)36
    4. (4)24
  17. Q17 · MCQ · ProbabilityOpen
    From a lot containing 10 defective and 90 non-defective bulbs, 8 bulbs are selected one by one with replacement. Then the probability of getting at least 7 defective bulbs is :-
    1. (1)7107\dfrac{7}{10^7}
    2. (2)81108\dfrac{81}{10^8}
    3. (3)67108\dfrac{67}{10^8}
    4. (4)73108\dfrac{73}{10^8}
  18. Q18 · MCQ · StatisticsOpen
    The mean and variance of a data of 10 observations are 10 and 2, respectively. If an observation α\alpha in this data is replaced by β\beta, then the mean and variance become 10.1 and 1.99, respectively. Then α+β\alpha + \beta equals.
    1. (1)10
    2. (2)15
    3. (3)5
    4. (4)20
    We corrected a printing error in the original paper

    Source printed “If an observations α\alpha”.

  19. Let A1A_1 be the bounded area enclosed by the curves y=x2+2y = x^2 + 2, x+y=8x + y = 8 and yy-axis that lies in the first quadrant. Let A2A_2 be the bounded area enclosed by the curves y=x2+2y = x^2 + 2, y2=xy^2 = x, x=2x = 2, and yy-axis that lies in the first quadrant. Then A1−A2A_1 - A_2 is equal to
    1. (1)23(22+1)\dfrac23\left(2\sqrt2 + 1\right)
    2. (2)23(42+1)\dfrac23\left(4\sqrt2 + 1\right)
    3. (3)23(2+1)\dfrac23\left(\sqrt2 + 1\right)
    4. (4)23(32+1)\dfrac23\left(3\sqrt2 + 1\right)
  20. The number of the real solutions of the equation : x∣x+3∣+∣x−1∣−2=0x\lvert x + 3\rvert + \lvert x - 1\rvert - 2 = 0 is
    1. (1)3
    2. (2)2
    3. (3)5
    4. (4)4
  21. Q21 · Numerical · Differential EquationsOpen
    Let a differentiable function ff satisfy the equation ∫036f(tx36)dt=4αf(x).\int_0^{36} f\left(\dfrac{tx}{36}\right)dt = 4\alpha f(x). If y=f(x)y = f(x) is a standard parabola passing through the points (2,1)(2, 1) and (−4,β)(-4, \beta), Then βα\beta^{\alpha} is equal to .
  22. Q22 · Numerical · 3D GeometryOpen
    Let a line LL passing through the point P(1,1,1)P(1, 1, 1) be perpendicular to the lines x−44=y−11=z−11andx−171=y−711=z0.\dfrac{x - 4}{4} = \dfrac{y - 1}{1} = \dfrac{z - 1}{1} \quad\text{and}\quad \dfrac{x - 17}{1} = \dfrac{y - 71}{1} = \dfrac{z}{0}. Let the line LL intersect the yzyz-plane at the point QQ. Another line parallel to LL and passing through the point S(1,0,−1)S(1, 0, -1) intersects the yzyz-plane at the point RR. Then the square of the area of the parallelogram PQRSPQRS is equal to .
  23. The number of numbers greater than 5000, less than 9000 and divisible by 3, that can be formed using the digits 0, 1, 2, 5, 9, if the repetition of the digits is allowed, is .
  24. Let (2α,α)(2\alpha, \alpha) be the largest interval in which the function f(t)=∣t+1∣t2f(t) = \dfrac{\lvert t + 1\rvert}{t^2}, t<0t < 0, is strictly decreasing. Then the local maximum value of the function g(x)=2log⁡e(x−2)+αx2+4x−αg(x) = 2\log_e(x - 2) + \alpha x^2 + 4x - \alpha, x>2x > 2, is .
  25. Q25 · Numerical · Matrices & DeterminantsOpen
    The number of 3×23 \times 2 matrices AA, which can be formed using the elements of the set {−2,−1,0,1,2}\{-2, -1, 0,\allowbreak 1, 2\} such that the sum of all the diagonal elements of ATAA^{T}A is 5, is .