PhysicsJEE Main 24 Jan 2026, Shift 1·Q24·Numerical·Moderate

Newton's Laws of Motion · Friction

In the given figure the blocks A, B and C weigh 4 kg, 6 kg and 8 kg respectively. The co-efficient of sliding friction between any two surfaces is 0.5. The force

\vec F

required to slide the block C with constant speed is N. (Use

g = 10\ \mathrm{m/s^2}

)

We corrected a printing error in the original paper

Answer corrected; the source key is (210) — it holds A fixed (friction 20 N on A), but in the figure A rests free on B and moves with it: $T = 50$ N, $F = 90 + 50 + 50 = 190$ N; source printed “(Used $g = 10\ \mathrm{m/s^2}$ )”.

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Newton's Laws of Motion · Friction

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