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MathsJEE Main 24 Jan 2026, Shift 2·Q11·MCQ·Moderate

3D Geometry · Shortest distance between skew lines

The sum of all values of α\alpha, for which the shortest distance between the lines x+1α=y−2−1=z−4−αandxα=y−12=z−12α\frac{x + 1}{\alpha} = \frac{y - 2}{-1} = \frac{z - 4}{-\alpha} \quad\text{and}\quad \frac{x}{\alpha} = \frac{y - 1}{2} = \frac{z - 1}{2\alpha} is 2\sqrt2, is
  1. (1)8
  2. (2)−6-6
  3. (3)6
  4. (4)−8-8

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