MathsJEE Main 6 Apr 2026, Shift 2·Q14·MCQ·Easy–moderate

3D Geometry · Shortest distance between skew lines

The shortest distance between the lines

\dfrac{x-4}{1} = \dfrac{y-3}{2} = \dfrac{z-2}{-3}

and

\dfrac{x+2}{2} = \dfrac{y-6}{4} = \dfrac{z-5}{-5}

is:

(1) $\dfrac{5\sqrt6}{6}$
(2) $2\sqrt5$
(3) $3\sqrt5$
(4) $4\sqrt5$

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