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MathsJEE Main 24 Jan 2026, Shift 2·Q6·MCQ·Moderate

Conic Sections · Reflection of parabola in line

Let the image of parabola x2=4yx^2 = 4y, in the line x−y=1x - y = 1 be (y+a)2=b(x−c)(y + a)^2 = b(x - c), a,b,c∈Na, b, c \in \mathbb{N}. Then a+b+ca + b + c is equal to
  1. (1)12
  2. (2)4
  3. (3)6
  4. (4)8
We corrected a printing error in the original paper

Source printed “(y+α)2=b(x−c)(y + \alpha)^2 = b(x - c)” (Greek α\alpha for the aa of “a,b,c∈Na, b, c \in \mathbb{N}” and “a+b+ca + b + c”).

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