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ChemistryJEE Main 28 Jan 2026, Shift 1·Q15·MCQ·Easy–moderate

Hydrocarbons · Peroxide effect anti-markovnikov addition

Ph−CH=CHX2→HBr(PhCOO)X2Product\ce{Ph-CH=CH2 ->[(PhCOO)2][HBr] Product}

Consider the above reaction

  • (A)The reaction proceeds through a more stable radical intermediate.
  • (B)The role of peroxide is to generate H˙\dot{\mathrm{H}} (Hydrogen radical).
  • (C)During this reaction, benzene is formed as a by-product.
  • (D)1-Bromo-2-phenylethane is formed as the minor product.
  • (E)The same reaction in absence of peroxide proceeds via carbocation intermediate.
Identify the correct statements. Choose the correct answer from the options given below:
  1. (1)A & E Only
  2. (2)A, B & D Only
  3. (3)C, D & E Only
  4. (4)A, C & E Only
We corrected a printing error in the original paper

Source printed “benzene is formed as a biproduct” and “1-Bromo-2-phenylethane is fanned as the minor product”.

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See the full 28 Jan 2026, Shift 1 paper