MathsJEE Main 28 Jan 2026, Shift 1·Q23·Numerical·Moderate

Inverse Trigonometry · Inverse trigonometric equations

k = \tan\left(\frac{\pi}{4} + \frac12\cos^{-1}\left(\frac23\right)\right) + \tan\left(\frac12\sin^{-1}\left(\frac23\right)\right)

then the number of solutions of the equation

\sin^{-1}(kx - 1) = \sin^{-1}x - \cos^{-1}x

is .

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