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PhysicsJEE Main 28 Jan 2026, Shift 1·Q24·Numerical·Easy–moderate

Ray Optics · Refraction

A convex lens of refractive index 1.5 and focal length f=18f = 18 cm is immersed in water. The difference in focal lengths of the given lens when it is in water and in air is α×f\alpha\times f. The value of α\alpha is .
(refractive index of water =4/3= 4/3)

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